Edexcel PH04 Questions
JAN 2012
http://www.edexcel.com/migrationdocuments/QP%20GCE%20Curriculum%202000/January%202012%20-%20QP/6PH04_01_que_20120307.pdf
Q5) Is it B because current is max at start and due to the fact its battery, which means it ll be losing energy and so with time charge decreases and decreases till 0?
Q9) I wont concentrate on this question itself ... i ve general questions
- is there antiparticle for say electron neutrino? if yes, whats its charge?
- how do i know whether i have to put a bar or not for antiparticles? coz sometimes its not a bar
- how is antimatter produced?
Q14) http://imgur.com/8lKvOhF
for part c ... do i just consider a point on the curvature like that? force is easy (in the middle), but just wanna make sure about the conventional current only.
Q15 bii -- not getting why AT ALL :/
June 2012
http://www.edexcel.com/migrationdocuments/QP%20GCE%20Curriculum%202000/June%202012%20-%20QP/6PH04_01_que_20120611.pdf
Q17) eii
how will horizontal component change if circular motion. I dunno, i m confused here really.
Q18) cvi)
So what if the mass is large and all that ? I m not understanding the process of finding top quark actually. Can you please explain me the collision process they do. I lack a lot in particle physics chapter. Sorry dude.
Jan 2011
http://www.edexcel.com/migrationdocuments/QP%20GCE%20Curriculum%202000/January%202011%20-%20QP/6PH04_01_que_20110127.pdf
Q18)
part a.
Will this gain 4 marks?
In this situation, if momentum is conserved, then the height reached by the last ball should be the same as the height to which the first one we suspended. Use a metre rule to measure the height? [obviously not even 2 marks :/]
But the markscheme strictly mentions that we need to talk about speed (why?)
And if i want to talk about speed, shall i say that to find speed use sqrt2gh ?
Please write to me (if you can) a good answer to such question, its annoying me really.
Q17)
part bii and c (cant get them) I ll reallt get like 1 mark in each maximum if this was in our exam.
Q16) aiv - I literally said its impossible to answer that question haha. wont proton attract?
http://www.edexcel.com/migrationdocuments/QP%20GCE%20Curriculum%202000/January%202012%20-%20QP/6PH04_01_que_20120307.pdf
Q5) Is it B because current is max at start and due to the fact its battery, which means it ll be losing energy and so with time charge decreases and decreases till 0?
Q9) I wont concentrate on this question itself ... i ve general questions
- is there antiparticle for say electron neutrino? if yes, whats its charge?
- how do i know whether i have to put a bar or not for antiparticles? coz sometimes its not a bar
- how is antimatter produced?
Q14) http://imgur.com/8lKvOhF
for part c ... do i just consider a point on the curvature like that? force is easy (in the middle), but just wanna make sure about the conventional current only.
Q15 bii -- not getting why AT ALL :/
June 2012
http://www.edexcel.com/migrationdocuments/QP%20GCE%20Curriculum%202000/June%202012%20-%20QP/6PH04_01_que_20120611.pdf
Q17) eii
how will horizontal component change if circular motion. I dunno, i m confused here really.
Q18) cvi)
So what if the mass is large and all that ? I m not understanding the process of finding top quark actually. Can you please explain me the collision process they do. I lack a lot in particle physics chapter. Sorry dude.
Jan 2011
http://www.edexcel.com/migrationdocuments/QP%20GCE%20Curriculum%202000/January%202011%20-%20QP/6PH04_01_que_20110127.pdf
Q18)
part a.
Will this gain 4 marks?
In this situation, if momentum is conserved, then the height reached by the last ball should be the same as the height to which the first one we suspended. Use a metre rule to measure the height? [obviously not even 2 marks :/]
But the markscheme strictly mentions that we need to talk about speed (why?)
And if i want to talk about speed, shall i say that to find speed use sqrt2gh ?
Please write to me (if you can) a good answer to such question, its annoying me really.
Q17)
part bii and c (cant get them) I ll reallt get like 1 mark in each maximum if this was in our exam.
Q16) aiv - I literally said its impossible to answer that question haha. wont proton attract?
Jan 2012
Q5- http://www.thestudentroom.co.uk/showthread.php?t=2564191
It may help to do q13 of paper jan11 as it is about same topic area and can help your understanding a lot of this question and the situation.
Q9-yes, electron antineutrino.
Neutrinos have neutral charge and since neutral charge has no opposite, antineutrinos are also neutral.
The antiparticles have a bar on top of them. An exception is the electron's antiparticle which instead of calling it antielectron we call it positron with no bar on top of it but a + charge on the top-right instead.
For antimatter production
Also pair production can be used, look
Q14c-yes, I'd go for middle as well like you drew as it's easy to tell the centripetal force (magnetic force) direction. I hope this answers what you want here.
Q15bii-I hate this question part, awful IMO. See this
http://www.thestudentroom.co.uk/showthread.php?t=2565526
June 2012
Q17eii-yes it will. As something moves in a circle due to the centripetal force on it, the horizontal component of velocity rises then decreases then rises...
Q18cvi-Large mass so large energy needed by E=mc^2. What collision process? In this question the following collisions occur
Proton+antiproton by collision
-->2 top quarks, move in opposite direction with same speed and have same mass, so no total momentum
Then the 2 top quarks decay rapidly into
-->2 muons + 4 jets + muon neutrino (not shown)
Jan 2011
Q18a-"identical solid metal balls" tells us that the balls have the same mass.
mv1=mv2, where ball 1 is the ball on the far left being suspended and ball 2 is the ball on the far right which becomes displaced.
v1 is the speed of ball 1 on impact.
v2 is like the speed of ball 2 after it bounces up after being whacked up and it about to hit the ball next to it [I THINK].
Both must be measured as said in the mark scheme.
Measure ball's change in vertical height from its suspension point to its impact point.
GPE loss = KE gain
mgdeltah=(1/2)mv^2
v=sqrt(2gdeltah)
Use this to calculate v1
Similarly, calculate v2
Cancelling the ms gives v1=v2. So to prove momentum being conserved (the first equation) you really need to just prove this second equation.
Something more concise and clear than that is probably needed, but I'm not good with experiments...
Q17bii-see if this explanation from a book helps (the image in the below post)
Q17c-the wording of this question is annoying, but what it asks isn't so complicated.
Explain why this provides a source of X-rays even though the speeds of the protons are constant.
[what's the source of X-rays then? -->free protons which are accelerating.]
Explain why free protons accelerate even though the speeds of these protons are constant, during their circular motion (as told).
Q16iv-See
http://www.thestudentroom.co.uk/showthread.php?t=2709185
DONE
Krishna
Q5- http://www.thestudentroom.co.uk/showthread.php?t=2564191
It may help to do q13 of paper jan11 as it is about same topic area and can help your understanding a lot of this question and the situation.
Q9-yes, electron antineutrino.
Neutrinos have neutral charge and since neutral charge has no opposite, antineutrinos are also neutral.
The antiparticles have a bar on top of them. An exception is the electron's antiparticle which instead of calling it antielectron we call it positron with no bar on top of it but a + charge on the top-right instead.
For antimatter production
Also pair production can be used, look
Q14c-yes, I'd go for middle as well like you drew as it's easy to tell the centripetal force (magnetic force) direction. I hope this answers what you want here.
Q15bii-I hate this question part, awful IMO. See this
http://www.thestudentroom.co.uk/showthread.php?t=2565526
June 2012
Q17eii-yes it will. As something moves in a circle due to the centripetal force on it, the horizontal component of velocity rises then decreases then rises...
Q18cvi-Large mass so large energy needed by E=mc^2. What collision process? In this question the following collisions occur
Proton+antiproton by collision
-->2 top quarks, move in opposite direction with same speed and have same mass, so no total momentum
Then the 2 top quarks decay rapidly into
-->2 muons + 4 jets + muon neutrino (not shown)
Jan 2011
Q18a-"identical solid metal balls" tells us that the balls have the same mass.
mv1=mv2, where ball 1 is the ball on the far left being suspended and ball 2 is the ball on the far right which becomes displaced.
v1 is the speed of ball 1 on impact.
v2 is like the speed of ball 2 after it bounces up after being whacked up and it about to hit the ball next to it [I THINK].
Both must be measured as said in the mark scheme.
Measure ball's change in vertical height from its suspension point to its impact point.
GPE loss = KE gain
mgdeltah=(1/2)mv^2
v=sqrt(2gdeltah)
Use this to calculate v1
Similarly, calculate v2
Cancelling the ms gives v1=v2. So to prove momentum being conserved (the first equation) you really need to just prove this second equation.
Something more concise and clear than that is probably needed, but I'm not good with experiments...
Q17bii-see if this explanation from a book helps (the image in the below post)
Q17c-the wording of this question is annoying, but what it asks isn't so complicated.
Explain why this provides a source of X-rays even though the speeds of the protons are constant.
[what's the source of X-rays then? -->free protons which are accelerating.]
Explain why free protons accelerate even though the speeds of these protons are constant, during their circular motion (as told).
Q16iv-See
http://www.thestudentroom.co.uk/showthread.php?t=2709185
DONE
Krishna
(edited 9 years ago)
Original post by krisshP
Q5- http://www.thestudentroom.co.uk/showthread.php?t=2564191
It may help to do q13 of paper jan11 as it is about same topic area and can help your understanding a lot of this question and the situation.
Q9-yes, electron antineutrino.
Neutrinos have neutral charge and since neutral charge has no opposite, antineutrinos are also neutral.
The antiparticles have a bar on top of them. An exception is the electron's antiparticle which instead of calling it antielectron we call it positron with no bar on top of it but a + charge on the top-right instead.
Krishna
It may help to do q13 of paper jan11 as it is about same topic area and can help your understanding a lot of this question and the situation.
Q9-yes, electron antineutrino.
Neutrinos have neutral charge and since neutral charge has no opposite, antineutrinos are also neutral.
The antiparticles have a bar on top of them. An exception is the electron's antiparticle which instead of calling it antielectron we call it positron with no bar on top of it but a + charge on the top-right instead.
Krishna
Hey thanks man!
I thought something completely different about this haha.
Now can you look at q9 please (the general question about particle phy)
Quick Reply
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