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Decision Linear Programming

Hey, just wandering with some of the inequalities they don't fit on the graph you are provided with :/ i was taught a cover up method way for working out how to plot the inequalities on the graph which i can do for all but ones which don't fit but don't remember how to fit it on the graph. Iv looked on the mark scheme and that doesn't really help :unimpressed: Thanks

Basically the value they gave is 4x+y (<=) 500 and on the y axis it only goes up to 200 and another x + 2y (<=) 300 where the x axis is only up to 200 aswell.

http://filestore.aqa.org.uk/subjects/AQA-MD01-W-QP-JUN07.PDF
Page 5 For Question And Page 11 For Graph Paper

http://filestore.aqa.org.uk/subjects/AQA-MD01-W-MS-JUN07.PDF
Page 7 mark scheme
Original post by ChocoholicCox
Hey, just wandering with some of the inequalities they don't fit on the graph you are provided with :/ i was taught a cover up method way for working out how to plot the inequalities on the graph which i can do for all but ones which don't fit but don't remember how to fit it on the graph. Iv looked on the mark scheme and that doesn't really help :unimpressed: Thanks

Basically the value they gave is 4x+y (<=) 500 and on the y axis it only goes up to 200 and another x + 2y (<=) 300 where the x axis is only up to 200 aswell.

http://filestore.aqa.org.uk/subjects/AQA-MD01-W-QP-JUN07.PDF
Page 5 For Question And Page 11 For Graph Paper

http://filestore.aqa.org.uk/subjects/AQA-MD01-W-MS-JUN07.PDF
Page 7 mark scheme


That's a bit odd, I don't think I've seen a question before where the lines don't completely fit on the graph. However, it's still not too hard. For the line 4x+y=500, plotting the x intercept is easy (125,0) and to get a second point, just choose a smaller x value (say 75) and find out the y value (200 in this case) and then draw an extended line going through those two points. Am I answering your question?
Original post by Chlorophile
That's a bit odd, I don't think I've seen a question before where the lines don't completely fit on the graph. However, it's still not too hard. For the line 4x+y=500, plotting the x intercept is easy (125,0) and to get a second point, just choose a smaller x value (say 75) and find out the y value (200 in this case) and then draw an extended line going through those two points. Am I answering your question?


Yes thats it :smile:, my teacher told me earlier and i forgot, thanks thats the exact method he used :biggrin:.

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