GCSE Edexcel physics - 12th June 2014

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Eradicating
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#81
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#81
(Original post by Akashi)
Range, I think, will be 15.8-16.2.
I got 15 omg! I never knew each little box was counted.

:hand:

Ok! How about comparing the isotopes? !

Was 59/27 C more stable then 60/27 C?

It said on the question cobalt 59 was more stable and was used in chain reaction. I think.

How would you compare the isoptes,

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SeniOyewumi
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#82
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#82
It was 7.8 or 7.83 depending on the amount of decimal places you round it up to. I think for the rope question talking about friction would get you a mark. Very good paper for me, my exams are over! I think I got absolutely everything on all the calculation questions.
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Eradicating
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#83
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#83
(Original post by SeniOyewumi)
It was 7.8 or 7.83 depending on the amount of decimal places you round it up to. I think for the rope question talking about friction would get you a mark. Very good paper for me, my exams are over! I think I got absolutely everything on all the calculation questions.
I got 7.8! What was question btw.

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"wise" not old
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#84
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#84
what do you think the grade boundaries will be like?
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SeniOyewumi
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#85
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#85
(Original post by Eradicating)
It was two marks! So do I get a mark for stating it transfers energy?

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All you had to say is that as the current travels over the resistor it transfers energy over it which has a heating effect and that's your two marks.
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Eradicating
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#86
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#86
(Original post by "wise" not old)
what do you think the grade boundaries will be like?
46-8/60

Upto 53/60.



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Eradicating
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#87
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#87
(Original post by SeniOyewumi)
All you had to say is that as the current travels over the resistor it transfers energy over it which has a heating effect and that's your two marks.
This is what I wrote.

I don't know we're people got ions colliding in lattice in current and resistor. Because that only happens inside metals.

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SeniOyewumi
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#88
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#88
(Original post by Parallex)
It was definitely 5.83 recurring.
No I'm afraid you've made a mistake somewhere in your working out, probably you subtracted the initial value from the final value when you're meant to subtract the final value from the initial value.

V= final value
U= initial value
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"wise" not old
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#89
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#89
(Original post by Eradicating)
46-8/60

Upto 53/60.



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I was hoping that they would be lower :confused:
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Eradicating
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#90
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#90
(Original post by SeniOyewumi)
No I'm afraid you've made a mistake somewhere in your working out, probably you subtracted the initial value from the final value when you're meant to subtract the final value from the initial value.

V= final value
U= initial value
He was right

T=v-u/a

He did that to get 5.38

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Eradicating
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#91
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#91
(Original post by "wise" not old)
I was hoping that they would be lower :confused:
Hopefully

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Akashi
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#92
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#92
(Original post by SeniOyewumi)
No I'm afraid you've made a mistake somewhere in your working out, probably you subtracted the initial value from the final value when you're meant to subtract the final value from the initial value.

V= final value
U= initial value
No, it was 5.83 recurring.

A = V-U/T = A x T = V-U =
T = V-U/A.

A = v-u/t =

Using T = V-U/A and getting 5.83 as our answer and inserting it into A = v-u/t we get 1.2 = 7/5.83. 7/5.83 gives us our corresponding unit for acceleration.
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Parallex
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#93
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#93
(Original post by SeniOyewumi)
No I'm afraid you've made a mistake somewhere in your working out, probably you subtracted the initial value from the final value when you're meant to subtract the final value from the initial value.

V= final value
U= initial value
I don't think I have, mate.

1.2 = 7/x
x has to be 5.83 recurring.
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SeniOyewumi
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#94
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#94
(Original post by Eradicating)
He was right

T=v-u/a

He did that to get 5.38

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I dunno how he got that answer, everyone in my class got 7.83.
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Eradicating
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#95
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#95
(Original post by SeniOyewumi)
I dunno how he got that answer, everyone in my class got 7.83.
Everyone in my class got 8.4 lool

We all times acceleration instead of dividng it.

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"wise" not old
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#96
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#96
Did anyone get a really large number for one of the first calculations, like 2 thousand and something.
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Akashi
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#97
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#97
If it is 8.4 then why is it that 1.2 = 7/8.4 will not work? It's not logically possible. A = V-U/T = A x T = V-U =
T = V-U/A.

A = v-u/t =
1.2 = 7/8.4 (using your method). 7/8.4 = 0.83.

Using T = V-U/A and getting 5.83 as our answer and inserting it into A = v-u/t we get 1.2 = 7/5.83. 7/5.83 gives us our corresponding unit for acceleration.
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#98
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#98
(Original post by "wise" not old)
Did anyone get a really large number for one of the first calculations, like 2 thousand and something.
Yes! 216000 I think

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Eradicating
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#99
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#99
(Original post by Akashi)
If it is 8.4 then why is it that 1.2 = 7/8.4 will not work? It's not logically possible. A = V-U/T = A x T = V-U =
T = V-U/A.

A = v-u/t =
1.2 = 7/8.4 (using your method). 7/8.4 = 0.83.

Using T = V-U/A and getting 5.83 as our answer and inserting it into A = v-u/t we get 1.2 = 7/5.83. 7/5.83 gives us our corresponding unit for acceleration.
We know we are wrong.

Chill,

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SeniOyewumi
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#100
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#100
For the nuclear fusion question about why it doesn't need to slow down, I said the neutrons are attached to a nuclei/atom of an element so I think I would have gotten 1 mark.
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