[br]\begin{enumerate}[br]\item[br]\begin{enumerate}[br]\item m = \dfrac{-1}{2} \hfill \textbf{\underline{[3]}} \\[br]\item \text{Any correct cartesian of: } x = \dfrac{t^{2}}{2} + 1, y = \dfrac{4}{t} - 1 \hfill \textbf{\underline{[2]}} \\[br]\end{enumerate}[br]\end{enumerate}[br]
[br]\begin{enumerate}[br]\setcounter{enumi}{1}[br]\item [br]\begin{enumerate}[br]\item A = 2, B = 3 \hfill \textbf{\underline{[3]}} \\[br]\item x^2 + 3ln({\dfrac{2x^{2} - x + 2}{5}}) + 1 \hfill \textbf{\underline{[4]}} \\[br]\end{enumerate}[br]\end{enumerate}[br]
[br]\begin{enumerate}[br]\setcounter{enumi}{2}[br]\item[br]\begin{enumerate}[br]\item (1-4x)^{\frac{1}{4}} = 1 - x - \dfrac{3}{2} x^2 \hfill \textbf{\underline{[2]}} \\[br]\item (2+3x)^{-3} = \dfrac{1}{8} - \dfrac{9}{16} x + \dfrac{27}{16} x^2 \hfill \textbf{\underline{[3]}} \\[br]\item \dfrac{1}{8} - \dfrac{11}{16} x + \dfrac{33}{16} x^2 \hfill \textbf{\underline{[2]}} \\[br]\end{enumerate}[br]\end{enumerate}[br]
[br]\begin{enumerate}[br]\setcounter{enumi}{3}[br]\item[br]\begin{enumerate}[br]\item A = 5000 \hfill \textbf{\underline{[1]}} \\[br]\item[br]\begin{enumerate}[br]\item \text{Show } p^{10} = 5 \hfill \textbf{\underline{[1]}} \\[br]\item V = £75000 \text{ in } 2018 \hfill \textbf{\underline{[4]}} \\[br]\end{enumerate}[br]\item [br]\begin{enumerate}[br]\item \text{Show } T =\dfrac{ln( \dfrac{5}{2})}{ln (\dfrac{p}{q})} \hfill \textbf{\underline{[4]}} \\[br]\item V = W \text{ in } 2023 \hfill \textbf{\underline{[1]}} \\[br]\end{enumerate}[br]\end{enumerate}[br]\end{enumerate}[br]
[br]\begin{enumerate}[br]\setcounter{enumi}{4}[br]\item[br]\begin{enumerate}[br]\item[br]\begin{enumerate}[br]\item A = 53.1, R = 5 \hfill \textbf{\underline{[3]}} \\[br]\item \theta = 18.5, 198.5 \hfill \textbf{\underline{[3]}} \\[br]\end{enumerate}[br]\item [br]\begin{enumerate}[br]\item \text{Show } ( tan{2\theta}tan{\theta} = 2 ) \equiv ( 2tan{\theta}^2 = 1 ) \hfill \textbf{\underline{[2]}} \\[br]\item \theta = 35.3, 144.7 \hfill \textbf{\underline{[2]}} \\[br]\end{enumerate}[br]\item[br]\begin{enumerate}[br]\item \text{Show } (2x-1) \text{ is a factor of } 8x^{3} - 4x + 1 \hfill \textbf{\underline{[1]}} \\[br]\item \text{Show } 4cos{2\theta}cos{\theta} + 1 = 8x^{3} - 4x + 1 \text{ where } x = cos{\theta} \hfill \textbf{\underline{[1]}} \\[br]\item cos{72} = \dfrac{\sqrt{5} - 1}{4} \hfill \textbf{\underline{[3]}} \\[br]\end{enumerate}[br]\end{enumerate}[br]
[br]\begin{enumerate}[br]\setcounter{enumi}{5}[br]\item [br]\begin{enumerate}[br]\item \text{Show } \overrightarrow{PQ} \text{ is parallel to } \left(\ \begin{array}{c} 1 \\ -1 \\ 1 \end{array}\right)\ \hfill \textbf{\underline{[3]}} \\[br]\item[br]\begin{enumerate}[br]\item R(3, -2, 4) \hfill \textbf{\underline{[3]}} \\[br]\item S(3, -5, 1) \hfill \textbf{\underline{[4]}} \\[br]\end{enumeratE}[br]\end{enumerate}[br]\end{enumerate}[br]
[br]\begin{enumerate}[br]\setcounter{enumi}{6}[br]\item [br]\begin{enumerate}[br]\item [br]\begin{enumerate}[br]\item \dfrac{dy}{dx} = \dfrac{-3ye^{3x}}{e^{3x}-2sin{2y}} \hfill \textbf{\underline{[6]}} \\[br]\item m = -\pi \hfill \textbf{\underline{[1]}} \\[br]\end{enumerate}[br]\item \text{y-intercept} = \dfrac{\pi}{4} - \dfrac{ln{2}}{\pi} \hfill \textbf{\underline{[2]}} \\[br]\end{enumerate}[br]\end{enumerate}[br]
[br]\begin{enumerate}[br]\setcounter{enumi}{7}[br]\item [br]\begin{enumerate}[br]\item \dfrac{3}{1-3x} + \dfrac{1}{1+x} - \dfrac{4}{(1+x)^{2}} \hfill \textbf{\underline{[4]}} \\[br]\item \dfrac{-1}{2} e^{-2y} = ln(\dfrac{1+x}{1-3x}) + \dfrac{4}{1+x} - \dfrac{9}{2} \hfill \textbf{\underline{[7]}} \\[br]\end{enumerate}[br]\end{enumerate}[br]
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