Graph of Kepler's Law

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#1
This is a question I had for maths but I figured it'd be more relevant in here.

2. Construct a table showing the mean distances and orbital periods for the eight planets. By plotting a suitable graph, find the law relating the orbital time to the mean distance.

Those are the two tables I made showing the orbital periods and mean distances and the relationship between the two but when I try to plot the graph using the logs of the original table I end up with this.

Any advice on what I'm doing wrong with the graph would be appreciated, thanks.
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7 years ago
#2
(Original post by Navm1)
This is a question I had for maths but I figured it'd be more relevant in here.

2. Construct a table showing the mean distances and orbital periods for the eight planets. By plotting a suitable graph, find the law relating the orbital time to the mean distance.

Those are the two tables I made showing the orbital periods and mean distances and the relationship between the two but when I try to plot the graph using the logs of the original table I end up with this.

Any advice on what I'm doing wrong with the graph would be appreciated, thanks.

How does the gradient relate to the relationship between the logs of the orbital period and mean distance?

What then is the relationship between the orbital period and mean distances?

EDIT: what is the distance in AU between the earth and the sun? What is the orbital period of the earth? (HINT: it's not 0)
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#3
(Original post by uberteknik)

How does the gradient relate to the relationship between the logs of the orbital period and mean distance?

What then is the relationship between the orbital period and mean distances?

EDIT: what is the distance in AU between the earth and the sun? What is the orbital period of the earth? (HINT: it's not 0)
the distance between the earth and sun in au is 1, and the orbital period is 1 year too.

The gradient of the line is 3/2 so the square of the orbital period is proportional to the cube of the distance?
0
7 years ago
#4
(Original post by Navm1)
the distance between the earth and sun in au is 1, and the orbital period is 1 year too.

The gradient of the line is 3/2 so the square of the orbital period is proportional to the cube of the distance?
Nearly.

The ratio of T2/R3 = constant

http://www.physicsclassroom.com/clas...r-s-Three-Laws
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