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Aqa unit 5 turning points official thread (unofficial markscheme)

Making a thread with all my calculations I remember all the calculation answers but for what questions a abit hard to remember but they are in order try get an unofficial markscheme going please fill in mistakes or blanks :smile:
1) around 200ish mev
B?????
2 constant 1.21X10^-4
B 8100 years
3 energy of particle 6.1x10^-21
B 87526.5m^2s^-2
4 energy of copper 16000j
Left over 13000j
Mass lost 5.6x10^-3
I got 1.69x10^-19 for the workfunction
Wavelength of electron 8.5x10^-12
Speed of probe 2.58x10^8
2.55 years
feel free to change I'm not Einstein :wink:
(edited 9 years ago)

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I got the (crms)2( c_{rms} )^2 question wrong but I'm pretty sure the units are m2s2m^2 s^{-2} as opposed to ms1ms^{-1}.
Original post by danielmoreton12
Making a thread with all my calculations I remember all the calculation answers but for what questions a abit hard to remember but they are in order try get an unofficial markscheme going please fill in mistakes or blanks :smile:
1) 1130 me
B mass 2x10^27 kg
2 constant 1.21X10^-4
B 8100 years
3 energy of particle 6.1x10^-21
B 87526.5ms
4 energy of copper 16000j
Left over 13000j
Mass lost 5.6x10^-3
I got 1.69x10^#19 for the next calculation but can't remember question any ideas?
Wavelength of electron 8.5x10^-12
Speed of probe 2.58x10^8
2.55 years
I also have a 2x10^-27 saved but cannot remember what question it was for feel free to change I'm not Einstein :wink:


I got 191 Mev for 1) and 3.39x10-28 for the mass
Original post by Khallil
I got the (crms)2( c_{rms} )^2 question wrong but I'm pretty sure the units are m2s2m^2 s^{-2} as opposed to ms1ms^{-1}.


Cheers I'll change it :smile:
Reply 4
For the question did you have to use 1/3Nm =NKT and then the N's cancel out? Can't remember my answer
Original post by Mandragoran
I got 191 Mev for 1) and 3.39x10-28 for the mass

Same as it gave you the binding energies and energy released is equal to the difference in binding energy, google says the average fission event is 200MeV so hopefully we are right
Original post by Mandragoran
I got 191 Mev for 1) and 3.39x10-28 for the mass


Everyone on the other threads say sane as me so I'll keep it for time been but if anyone else,says it's that I'll look into it :smile:
Reply 7
Original post by Seth James
Same as it gave you the binding energies and energy released is equal to the difference in binding energy, google says the average fission event is 200MeV so hopefully we are right


It gave you the binding energies per nucleon so you had to times by the number of nucleons
Original post by danielmoreton12
Everyone on the other threads say sane as me so I'll keep it for time been but if anyone else,says it's that I'll look into it :smile:



How did you calculate it as 1130MeV?
Because if you just took the binding energies away from each other, it was binding energy per nucleon. But I don't know why it was 3 marks anyway...
(edited 9 years ago)
Original post by Fread123
It gave you the binding energies per nucleon so you had to times by the number of nucleons


Yeah sorry forgot to say, I did do that thank god, what answer did you get?
Original post by MelonBath
How did you calculate it as 1130MeV?
Because if you just took the binding energies away from each other, it was binding energy per nucleon. But I don't know why it was 3 marks anyway...

I think I used neutrons in my calculations which I don't don't think was the right thing to do... I'll change it :smile:
Original post by MelonBath
...


I got 190.6 or something like that for the energy released in MeV. I'm pretty sure we had to use E=mc^2 thereafter to find the mass but before that, we needed to convert E to Joules by multiplying by 1.6 x 10^(-13). Also, for the first part, we had to multiply each of the binding energies per nucleon by the number of nucleons in each of the nuclei.
Reply 12
Original post by danielmoreton12
Making a thread with all my calculations I remember all the calculation answers but for what questions a abit hard to remember but they are in order try get an unofficial markscheme going please fill in mistakes or blanks :smile:
1) 1130 me
B mass 2x10^27 kg
2 constant 1.21X10^-4
B 8100 years
3 energy of particle 6.1x10^-21
B 87526.5m^2s^-2
4 energy of copper 16000j
Left over 13000j
Mass lost 5.6x10^-3
I got 1.69x10^#19 for the next calculation but can't remember question any ideas?
Wavelength of electron 8.5x10^-12
Speed of probe 2.58x10^8
2.55 years
I also have a 2x10^-27 saved but cannot remember what question it was for feel free to change I'm not Einstein :wink:


What was the question about the probe? I don't recall this and have a feeling I've somehow missed this page?!
If anyone disagrees please say want to make it as accurate as possible :smile:
Original post by Jonj1
What was the question about the probe? I don't recall this and have a feeling I've somehow missed this page?!


Last page about a probe going to a planet? You may have missed it :/
Original post by danielmoreton12
Making a thread with all my calculations I remember all the calculation answers but for what questions a abit hard to remember but they are in order try get an unofficial markscheme going please fill in mistakes or blanks :smile:
1) around 200ish mev
B?????
2 constant 1.21X10^-4
B 8100 years
3 energy of particle 6.1x10^-21
B 87526.5m^2s^-2
4 energy of copper 16000j
Left over 13000j
Mass lost 5.6x10^-3
I got 1.69x10^#19 for the next calculation but can't remember question any ideas?
Wavelength of electron 8.5x10^-12
Speed of probe 2.58x10^8
2.55 years
feel free to change I'm not Einstein :wink:


The question that you 1.69*10^(-19) was finding the work function of the metal.
Reply 16
Original post by danielmoreton12
Last page about a probe going to a planet? You may have missed it :/


Wow I'm an idiot, this was on section A right?
Original post by Fread123
For the question did you have to use 1/3Nm =NKT and then the N's cancel out? Can't remember my answer


I used 3/2kT=1/2m(Crms)^2, but both routes probably get the same outcome.
what was the answer to the question about how the type of particle affects the specific charge? And the one about how the increase in positive potential at T decreases the ammeter reading?
Original post by MelonBath
The question that you 1.69*10^(-19) was finding the work function of the metal.


Cheers mate :wink:

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