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#1
2x + 6 / x^2 + 6x + 9
5x - 20/ x^2 + 2x - 24
0
6 years ago
#2
For the second one factorise top and bottom

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0
6 years ago
#3
The first one: 2x is equal to 12x/6. Wrong thing. You need to factorise the RHS and simplify the fraction im wrong for this one

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0
6 years ago
#4
(Original post by Frodokins)
2x = 6 / x^2 + 6x + 9
5x - 20/ x^2 + 2x - 24
How far have you got so far?
0
6 years ago
#5
(Original post by Frodokins)
2x = 6 / x^2 + 6x + 9
5x - 20/ x^2 + 2x - 24
Do you mean ?

If so, just multiply both sides by the denominator and rearrange to set one side to 0. Then use the factor theorem to spot one solution and divide through to obtain a quadratic from which you can calculate the other roots.

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#6
(Original post by Caitlin_3008)
How far have you got so far?
1) (x + 3) (x+3) ---- dont know what to do next
2) (x _ 6) (x _ 4) ----- dont know what to do next or how to format answer
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#7
(Original post by Arithmeticae)
Do you mean ?

If so, just multiply both sides by the denominator and rearrange to set one side to 0. Then use the factor theorem to spot one solution and divide through to obtain a quadratic from which you can calculate the other roots.

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sorry! i mean 2x + , not =
0
6 years ago
#8
(Original post by Frodokins)
sorry! i mean 2x + , not =
Oh, right.

The first thing you need to know is that it is definitely not an equation if you meant a + sign and there is nothing to solve.

You can factorize the the top and bottom and cancel out common factors to simplify it.
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6 years ago
#9
2/(x+3) and x/(x+6)
0
6 years ago
#10
(Original post by Frodokins)
2x + 6 / x^2 + 6x + 9
5x - 20/ x^2 + 2x - 24
Those aren't equations!

What are you supposed to be doing?
0
6 years ago
#11
Can you post the entire question. As you have stated it, there is nothing to do as there is no equation to solve.
0
6 years ago
#12
What is the question - to factorise/simplify it?
0
6 years ago
#13
Shivers math! My worst! lol
Let's see if I can do it...
0
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