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# Urgent Help with Calculus! Watch

1. is f(x) = 1/3-x an odd or even function?
2. (Original post by bernard96)
is f(x) = 1/3-x an odd or even function?
Well, what happens when you replace x with -x? Can you relate f(-x) to f(x) in any way? Does f(x) = f(-x)? Does f(-x) = -f(x)?
3. when i replace x with -x,

f(-x)
= 1 / 3- (-x)
= 1 / 3 + x
= 1 / - (-3 - X)
= - ( 1/ -3-X )

Its neither right?

since f(-x) is not equal to f(x) and -f(x)?
4. (Original post by bernard96)
when i replace x with -x,

f(-x)
= 1 / 3- (-x)
= 1 / 3 + x
= 1 / - (-3 - X)
= - ( 1/ -3-X )

Its neither right?

since f(-x) is not equal to f(x) and -f(x)?
Your final answer ("neither") is correct, but your working is decidedly ambiguous. It works if your original function was and not , as I originally took it to be.

The answer to the question "is f an odd or even function?" is "no".
5. The original function is . Then, it is neither, correct? Thank you so much !
6. (Original post by bernard96)
...
Exactly.

so isn't an even function.

so isn't odd either.

Now we can conclude that is neither odd, nor even.

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