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    6^2x-1 = 9^x+3
    (2x-1)lg6 = (x+3)lg9
    im stuck at this point, i forgot what to do, can anyone please help
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    Put all the x terms on the left and the other terms on the right.

    Full solution below:
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    (2x-1)lg6 = (x+3)lg9
    2x lg6 - lg6 = x lg9 + 3lg9
    x (2 lg6 - lg9) = 3 lg9 + lg6
    x = (3 lg9 + lg6) / (2 lg6 - lg9).
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    If you want to work it out,

    log2 X =(log10 X)/(log10 2)
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    (Original post by ORIGINAL)
    6^2x-1 = 9^x+3
    (2x-1)lg6 = (x+3)lg9
    im stuck at this point, i forgot what to do, can anyone please help
    lg6=lg2+lg3 & lg9=lg3+lg3
    Expand both sides, then put x on the same side.
    You will get the result.
    (sometimes you don't get a nice result, really.)
 
 
 

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