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    i am stuck on this question, not really sure how to approach it. i tried to find the height of the triangle, but couldn't work it out because i had too many unknowns. i can't figure out a way to use the info to find the answer.

    the answer, for those who are wondering is D
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    Who is this aimed at? 15-16 year olds or 16-18? You know all the angles in the centre are 90 degrees (or you should). And the only values you have are 8 and 12. I'd work with them and attempt to solve them using the info available.I'm giving it an attempt.
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    (Original post by The Big Stone)

    i am stuck on this question, not really sure how to approach it. i tried to find the height of the triangle, but couldn't work it out because i had too many unknowns. i can't figure out a way to use the info to find the answer.

    the answer, for those who are wondering is D
    You can find the area of the quadrilateral TSRQ with the information given

    That eliminates answers A, B, and C

    It also suggests that E is impossible
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    (Original post by MathMeister)
    It is no coincidence 12*8= 96 and 96/2= the answer
    96/2 = 48
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    (Original post by The Big Stone)

    i am stuck on this question, not really sure how to approach it. i tried to find the height of the triangle, but couldn't work it out because i had too many unknowns. i can't figure out a way to use the info to find the answer.

    the answer, for those who are wondering is D
    1. Note that triangles PQS and QSR have the same base and height. (So what?)
    2. Note that the medians of a triangle intersect each other in the ratio 2:1
    3. Note that you have a bunch of right triangles to work with.
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    any tips? hints?
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    (Original post by MathMeister)
    any tips? hints?
    Between post 3 and 7 there are all the hints needed
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    (Original post by TenOfThem)
    You can find the area of the quadrilateral TSRQ with the information given

    That eliminates answers A, B, and C

    It also suggests that E is impossible
    Okay, but imagine i wasn't given possible answers, i couldn't eliminate any answers, so how would i get to 64?
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    (Original post by The Big Stone)
    Okay, but imagine i wasn't given possible answers, i couldn't eliminate any answers, so how would i get to 64?
    Well I would use the similar triangles
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    Thats exactly what i thought of!!!
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    (Original post by The Big Stone)
    Okay, but imagine i wasn't given possible answers, i couldn't eliminate any answers, so how would i get to 64?
    Did you not understand the hints I gave earlier? I've done most of the work for you there.
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    (Original post by atsruser)
    Did you not understand the hints I gave earlier? I've done most of the work for you there.
    Interestingly you went in a completely different direction to me
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    Is this a senior challenge question?
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    I thought so.
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    (Original post by Super199)
    Is this a senior challenge question?
    I would have thought intermediate the knowledge required is not a high level
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    (Original post by atsruser)
    Did you not understand the hints I gave earlier? I've done most of the work for you there.
    i understand now. the 2 triangles have the equal area, and so working out the area of one x2 would give you the answer, also the ratios you work out the lengths, but wouldn't it be easier to say that PTR = QTR instead of saying QSR=PQS ?
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    (Original post by Super199)
    Is this a senior challenge question?
    Yh, but it was from 2007
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    (Original post by TenOfThem)
    Interestingly you went in a completely different direction to me
    What's your solution?
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    (Original post by The Big Stone)
    i understand now. the 2 triangles have the equal area, and so working out the area of one x2 would give you the answer, also the ratios you work out the lengths,
    Right.

    but wouldn't it be easier to say that PTR = QTR instead of saying QSR=PQS ?
    Yes, a bit. Once I found a solution, I couldn't be bothered to see if there was a quicker one though.
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    (Original post by atsruser)
    Yes, a bit. Once I found a solution, I couldn't be bothered to see if there was a quicker one though.
    kay, thanks.
 
 
 
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