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    Draw and name the shape of the TlBr52− ion.
    From AQA June 13 Unit 1 paper.
    What is the method for doing this? I'm fairly new to this stuff and only know the basics of the angles and structures of simple molecules.

    Thanks in advance
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    I think it is trigonal bipyramidal, we just learnt the shapes of molecules with varying amounts of bonding pairs/line pairs
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    From the periodic table we know Tl has 3 outer electrons. As it has a 2- charge this means it now has 5 on the outer shell, allowing it to bond with 5 other atoms, in this case Br, hence TlBr52-

    The shape for an ion with 5 atoms bonded to it is trigonal byprimdal.

    You just learn which shapes molecules have given the numbers of bonding elections they possess, so 5 bonding pairs will give a trigonal bypyrimdal shape, 3 will be trigonal planar, 2 will be linear and so on (not accounting for lone pairs)
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    (Original post by Super199)
    Draw and name the shape of the TlBr52− ion.
    From AQA June 13 Unit 1 paper.
    What is the method for doing this? I'm fairly new to this stuff and only know the basics of the angles and structures of simple molecules.

    Thanks in advance
    If you go onto youtube "Colourful Solutions" there are many videos explaining how to draw shapes of molecules ...
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    (Original post by TajwarC)
    From the periodic table we know Tl has 3 outer electrons. As it has a 2- charge this means it now has 5 on the outer shell, allowing it to bond with 5 other atoms, in this case Br, hence TlBr52-

    The shape for an ion with 5 atoms bonded to it is trigonal byprimdal.

    You just learn which shapes molecules have given the numbers of bonding elections they possess, so 5 bonding pairs will give a trigonal bypyrimdal shape, 3 will be trigonal planar, 2 will be linear and so on (not accounting for lone pairs)
    Right cheers boss. Did you do AS this year?
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    (Original post by Super199)
    Right cheers boss. Did you do AS this year?
    Yeah, are you about to start?
 
 
 
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