# Logarithms

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#1
(Given that log (base 3) x=2 determine the value of y for which log (base 3) (y+4)=2.
Please help. I do not know what to do when there are 2 values in that position.
I actually figured it out. But i'd like to know why the textbook only says it's Y=12, not y=-3.. y=-3 seems to work as well. So is the textbook answer wrong?
0
6 years ago
#2
(Original post by MathMeister)
(Given that log (base 3) x=2 determine the value of y for which log (base 3) (y+4)=2.
Please help. I do not know what to do when there are 2 values in that position.
I actually figured it out. But i'd like to know why the textbook only says it's Y=12, not y=-3.. y=-3 seems to work as well. So is the textbook answer wrong?
Not sure what the x bit is about Means So I am not sure where your or the books answers come from

Can you type in the exact question
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#3
Ignore the x. I thought the question carried on from the first one- but it seems it didn't.
Uhhm.. Yes, you are right that Means , however since the logs in the equation are being subtracted from each other, you divide them and you get log (base 3) ([y^2)/(y+4)] =2 ... Then I solved it.
0
6 years ago
#4
(Original post by MathMeister)
Ignore the x. I thought the question carried on from the first one- but it seems it didn't.
Uhhm.. Yes, you are right that Means , however since the logs in the equation are being subtracted from each other, you divide them and you get log (base 3) ([y^2)/(y+4)] =2 ... Then I solved it.
mm you sure that is the question? Where in the book is it from?
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#5
(Original post by Super199)
mm you sure that is the question? Where in the book is it from?
Yes, Its on page 49 of the C2 edexcel modular book, chapter 3.6 Mixed exersise 3G question 4b 0
6 years ago
#6
(Original post by MathMeister)
Yes, Its on page 49 of the C2 edexcel modular book, chapter 3.6 Mixed exersise 3G question 4b The question is: which isn't what you posted

Use power rule
Then the subtraction one
anti-log

You should get a quadratic, solve for y. One of your answers will be invalid because you cannot log a negative.
Post your workings if you get stuck 0
6 years ago
#7
(Original post by MathMeister)
Ignore the x. I thought the question carried on from the first one- but it seems it didn't.
Uhhm.. Yes, you are right that Means ,

however since the logs in the equation are being subtracted from each other, you divide them and you get log (base 3) ([y^2)/(y+4)] =2
... Then I solved it.
I do not mean to be rude but you really need to ask the question that you want answering
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