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    • Thread Starter

    I'll link an attachment below and I'll explain what I've done so far

    For the 1st 2 marker question I understand the opposite angle is 73 degrees because it's isocles and that's all I've gotten.
    However on question 2 I've wrote so far...
    (not sure if its correct)
    all angles are 60 degrees in the triangles and the sides are 10. So I should half the rectangle into a right angled triangle and the side would be 20 cm and the angle 90 degrees and use tan?
    but that's where im stuck
    please explain and offer me guidance
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    • Thread Starter

    (Original post by AlphaNick)
    You're correct so far, ∠ACN (assume N is the midpoint of length X) is equal to 73°
    You should then realise that it is possible to work out length x with the trigonometry equations:

    Since you have the hypotenuse and the angle, and you're trying to work out the adjacent side, you should use the second equation listed.

    Rearrange it to get:
    (the dot means times by)

    So do cos(73)*9

    Then remember to double it to find the total length of x.

    Yeah, all angles in that upper triangle are 60°
    So you should now have an angle of 30° and a side of 19cm, use the third equation I listed previously to work it out.

    thanks for your help
    is 1) = 5.2 cm correct
    and 2) = 22 cm correct??

    (Original post by AlphaNick)
    1 should be 5.26, so it would round to 5.3 at 2sf, be careful there but it looks fine.

    2 I got 32.9 cm, check again
    I agree
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