# How do i solve this Volume question- Chemistry

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#1
I am revising A-level Chemistry and the question states:

Ammonia is bought as “880 ammonia” (a solution of density 0.880 g cm-3), whose content is 28% ammonia (i.e. it contains 280 g ammonia per kilogram of solution). What volume of the “880 ammonia” solution would you need to prepare 1.0 dm3 of 2.0 mol dm-3 ammonia solution ?

How would i get the answer: 0.138 L

Here are some equations:

n=m/Mr n=C x V/1000 therefore V=n/c x1000
0
7 years ago
#2
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0
7 years ago
#3
(Original post by mind)
I am revising A-level Chemistry and the question states:

Ammonia is bought as “880 ammonia” (a solution of density 0.880 g cm-3), whose content is 28% ammonia (i.e. it contains 280 g ammonia per kilogram of solution). What volume of the “880 ammonia” solution would you need to prepare 1.0 dm3 of 2.0 mol dm-3 ammonia solution ?

How would i get the answer: 0.138 L

Here are some equations:

n=m/Mr n=C x V/1000 therefore V=n/c x1000
Find out how many moles of ammonia is needed for your target solution.

Now work out the molarity of your stock solution.

Now determine what volume of your stock solution contains the number of moles needed for your target solution.
0
7 years ago
#4
Alternatively, instead of finding molarity of the 880 solution, find what mass of the ammonia is needed (from number of moles in the target solution), then find what mass of 28% solution contains needed mass of ammonia, and finally find volume of that solution from known density.

This approach doesn't call for finding or deriving conversion equation between w/w percentage and molarity - so I would get the final answer faster this way. YMMV.
0
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