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# Limits question Watch

1. limit as n tends to infinity

((e^-n+n)/n+2))^2n

I thought if I found the limit of the bracket to be 1 and 1^2n is always 1 therefore the limit is 1?
2. (Original post by CammieInfinity)
limit as n tends to infinity

((e^-n+n)/n+2))^2n

I thought if I found the limit of the bracket to be 1 and 1^2n is always 1 therefore the limit is 1?
Try a large number for n on your calculator. It isn't 1 is it?
3. I can't remember much about limits but this can be turned into:

where

Your notation is ambiguous by the way - you could do with a bracket around n + 2.

4. How did you get it to 1+1/x? The division yields (1+(e^(-n)-2/n+2))^2n
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5. (Original post by CammieInfinity)
How did you get it to 1+1/x? The division yields (1+(e^(-n)-2/n+2))^2n
If you still can't be bothered to use unambiguous notation I can't be bothered to make the effort to try to read that. I used the fact that tends to zero as x tends to infinity.
6. I got it despite your short comings

7. (Original post by CammieInfinity)
...
Don't start being unpleasant or your time here could be very short.
8. Oh no say it isn't so, whatever will I do without your guidance. Plus i have several e-mails and signing up takes two ticks - you're fighting a lost battle hun. Xoxo

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