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# Interesting Maths Problem watch

1. I recently came across an interewsting maths problem, which challenged you to arrange three 8s to make all of the numbers from 1 to 9, inclusive. I have got all the numbers, except for arranging three 8s to get 3.

e.g. 8 + 8 - 8 = 8
sqrt(8x8)/8 = 1

Some are easy, like the above, but others require more difficult solutions. If anyone can provide me with an answer to make three i would be extremely grateful.

I hope this challenges some other people who might wish to undertake it.

Chris
2. Using which arithmetic operators? +, -, *, / and sqrt I presume?
3. What about ! as in 4! = 1+2+3+4
Can u use that ?
4. If cube roots are allowed then 8/8 + cuberoot(8) = 3 ?
5. (Original post by Hollings)
I recently came across an interewsting maths problem, which challenged you to arrange three 8s to make all of the numbers from 1 to 9, inclusive. I have got all the numbers, except for arranging three 8s to get 3.

e.g. 8 + 8 - 8 = 8
sqrt(8x8)/8 = 1

Some are easy, like the above, but others require more difficult solutions. If anyone can provide me with an answer to make three i would be extremely grateful.

I hope this challenges some other people who might wish to undertake it.

Chris

or if you cant use cuberoots, just square root the one for 9.
6. (Original post by scarlet ibis)
What about ! as in 4! = 1+2+3+4
Can u use that ?
4! = 4 x 3 x 2 x 1
7. sqrt(8/8+8)=3
8. Sorry, i should have mentioned you can use any operator, e.g. !, sqrt, ^, etc., but not any other numbers - so you cant use cube root, square the number and so on.

I found the answer not too long after posting this thread - ([sqrt(8+8)]!)/8 - i didnt think of just square rooting the one for 9 !!

Chris

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