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    I recently came across an interewsting maths problem, which challenged you to arrange three 8s to make all of the numbers from 1 to 9, inclusive. I have got all the numbers, except for arranging three 8s to get 3.

    e.g. 8 + 8 - 8 = 8
    sqrt(8x8)/8 = 1

    Some are easy, like the above, but others require more difficult solutions. If anyone can provide me with an answer to make three i would be extremely grateful.

    I hope this challenges some other people who might wish to undertake it.

    Chris
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    Using which arithmetic operators? +, -, *, / and sqrt I presume?
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    What about ! as in 4! = 1+2+3+4
    Can u use that ?
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    If cube roots are allowed then 8/8 + cuberoot(8) = 3 ?
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    (Original post by Hollings)
    I recently came across an interewsting maths problem, which challenged you to arrange three 8s to make all of the numbers from 1 to 9, inclusive. I have got all the numbers, except for arranging three 8s to get 3.

    e.g. 8 + 8 - 8 = 8
    sqrt(8x8)/8 = 1

    Some are easy, like the above, but others require more difficult solutions. If anyone can provide me with an answer to make three i would be extremely grateful.

    I hope this challenges some other people who might wish to undertake it.

    Chris

    or if you cant use cuberoots, just square root the one for 9.
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    (Original post by scarlet ibis)
    What about ! as in 4! = 1+2+3+4
    Can u use that ?
    4! = 4 x 3 x 2 x 1
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    sqrt(8/8+8)=3
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    Sorry, i should have mentioned you can use any operator, e.g. !, sqrt, ^, etc., but not any other numbers - so you cant use cube root, square the number and so on.

    I found the answer not too long after posting this thread - ([sqrt(8+8)]!)/8 - i didnt think of just square rooting the one for 9 !!

    Chris
 
 
 
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