AQA chemistry today - module 4 Watch

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#1
Report 15 years ago
#1
did anyone else do this?

it was AWFUL!! i couldn't do any of section B, so i just had to make random guesses! i really hope the grade boundaries come down for this one - how did everyone else find it? so not looking fiorward to mod 5 and synoptic on tuesday!
m1985
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#2
Report 15 years ago
#2
i found it terrible too. got stuck and panicked early on. what a nightmare. hated the whole of section B it was soooooooo hard. what did u thik of the first half?
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#3
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the first half was ok-ish i guess. i haven;'t done that well though and i need an A!! bugger! i'm glad the calculations weren't too difficult (although i still messed up one of them!). there were a couple of mechanisms i really couldn't do. and i couldn't draw that isomer. for question 1, when you had to fid the order of A and B i got A being 2 and B being 1. i'm not sure if that's right. and i that the overall order for teh q before it was 2.
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FOR THAT CHEM PAPER I GOT THE PVERALL BEIN 2!! BUT I GOT ORDER 2 FOR A AND ZERO ORDER FOR B!!!! THATS PROB WRONG THO!!!
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I think I hammered the Organic on this paper and everything came out alright. The Physical was a little rusty though. I put 2 and 1 for those orders of reaction as a guess so that I would have things to put in my rate equation. I've been told that 2 was right so therefore I think that makes me what is know as a "lucky git" ^_^
*Simran*
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#6
i thot the exam woz hard, section B in particular!

Do the grade boundaries realli go down if a lot of ppl dont do well in the exam? i thot they remained "fixed" n u have to get over 80% to get an A in the exam, whether or not ppl found it hard??????
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Mark Gillan
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Well, the overall order of reaction was 2.

Then it said that when the concentration of A was trebled, and the concentration of B was halved, the rate increased by a factor of nine. This means the order w.r.t. A was 2, and w.r.t. B it was 0.

So the rate equation was

R = k[A]^2

I think!
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