transposition of formulae involving logs and exponentials

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#1
hi could someone assist with this:

n=R + 10 ln

i have to change the subject to p1

this is my working

R goes over to the other side and subtracts with with n

R-n =10 ln

then i remove the fraction and take p2 over and multiply it

p2 (R-n) = 10 ln P1

take the e 10 on both sides by dividing it

p2 (R-n)
----------
E 10

problem solved

is this correct?

0
6 years ago
#2
(Original post by hitch1983)
hi could someone assist with this
N=R + 10 ln
N-R= 10 ln
= ln

so...now just use the fact that a = e ln(a)

= e
(as in e to the power of )

p1 = p2 X
e
- ()

It won't let me write a fraction within a fraction..
0
#3
thanks for the help
0
6 years ago
#4
(Original post by Complex solution)
N=R + 10 ln
N-R= 10 ln
= ln

so...now just use the fact that a = e ln(a)

= e
(as in e to the power of )

p1 = p2 X
e
- ()

It won't let me write a fraction within a fraction..
What do you mean by "a fraction within a fraction"? Do you mean like this? or did you want to write
0
6 years ago
#5
(Original post by brianeverit)
What do you mean by "a fraction within a fraction"? Do you mean like this? or did you want to write
(Original post by arkanm)
Probably the latter, hence "fraction within a fraction"
Yes, 'twas the latter.

I wish there was a tutorial for writing maths equations in forums.
0
6 years ago
#6
Thanks
1
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