Consider a disc as you have described in the y-z plane, perpendicular to the x-axis with its centre at the origin, charge density n, radius R.
Now find the potential at a point x along the x-axis, which is the sum of the potential from all the charge area elements on the disc, which are given by n*(r dr dt), where r is the distance along a radius on the disc, and t is the angle from the y-axis.
dVx = dq/4*pi*e0*|a| = (n*r dr dt)/[4*pi*e0*sqrt(x2 + r2)]
∫dVx = Vx = n/(4*pi*e0) * ∫02pidt * ∫0R r dr/sqrt(x2 + r2)
Vx= n/(4*e0) * sqrt(x2 + R2)
So, the electric field along the x-axis is given by Ex = -dVx/dx:
|Ex| = [n*x/(2*e0)] / sqrt(x2 + R2)
So this gives you the electric field at an axial distance x from the disc. Hope this helps you.