The Student Room Group

Maths Tricky Question?

Hello everyone,

Can anyone tell me the answer of this question and also explain how you got it? Thanks Neorah


Question:

A trainee in a garden centre monitors the growth of a young plant. The height of the plant is found to increase by 15% to 24 cm.

Find the height of the plant when the trainee started to monitor it.


This question is worth 1 mark.
Reply 1
Original post by Neorah
Hello everyone,

Can anyone tell me the answer of this question and also explain how you got it? Thanks Neorah


Question:

A trainee in a garden centre monitors the growth of a young plant. The height of the plant is found to increase by 15% to 24 cm.

Find the height of the plant when the trainee started to monitor it.


This question is worth 1 mark.


I'll just guide you to the answer? Call initial height x and what do you multiply it by to get 24?
Original post by Neorah
Hello everyone,

Can anyone tell me the answer of this question and also explain how you got it? Thanks Neorah

Question:

A trainee in a garden centre monitors the growth of a young plant. The height of the plant is found to increase by 15% to 24 cm.

Find the height of the plant when the trainee started to monitor it.

This question is worth 1 mark.


Do you understand reverse percentages?

What is the multiplier for a 15% increase?

What operation do you need to do to go back in time?

Peculiar question by the way - the answer isn't very nice.
(edited 9 years ago)
Reply 3
Hello mr.m

I have no idea how reverse percentages work could you please explain to me so i can work it out?
Original post by Neorah
Hello mr.m

I have no idea how reverse percentages work could you please explain to me so i can work it out?


If I said that something was 20cm and was then increased by 15% - what would you do to find the increased height?
If it has increased 15% it means it is now at 115% at 24cm. To find the original high the monitored it at, you do 2 simple calculations..
(edited 9 years ago)
Reply 6
Original post by TenOfThem
If I said that something was 20cm and was then increased by 15% - what would you do to find the increased height?

1.15×20 =23 cm
Original post by Kyle-McGrory
If it has increased 15% it means it is now at 115% at 24cm. To find the original high the monitored it at, you do 2 simple calculations


Perhaps you are unaware of the forum guidelines that ask us not to give full solutions
Original post by Neorah
Original post by TenOfThem
If I said that something was 20cm and was then increased by 15% - what would you do to find the increased height?


1.15×20 =23 cm


Excellent

So in your question (something) x 1.15 = 24

Can you see what you have to do to work back to the "something"?
Original post by Neorah
1.15×20 =23 cm


Yes so if you want to go back in time you do 23÷1.15=2023 \div 1.15 = 20
Reply 10
Original post by Mr M
Yes so if you want to go back in time you do 23÷1.15=2023 \div 1.15 = 20


Alright thank you so much guys!
can someone help me with this question


question:
A man can travel to work either by train or by car. The journey is 90km. The train travels 15 km/h faster than the car, and completes the journey in half an hour less time. Find the speed of the car on its journey
Do 24 x 0.85 as that subtracts the 15% to find the original height :smile:


Posted from TSR Mobile
Original post by dream_and_wish
Do 24 x 0.85 as that subtracts the 15% to find the original height :smile:


This is incorrect

Please read the thread
Original post by dream_and_wish
Do 24 x 0.85 as that subtracts the 15% to find the original height :smile:


Posted from TSR Mobile


This would take 15% off the new value, you are looking for what you add 15% to to reach this new value.

OP think of how you would undo a multiplication
To find the original height divide by 115 and times by 100

By dividing by 115 it reduces the original 115% to 1% then times by 100 to get 100%

E.g. If a plant was increased by 20% and it's at 24 (Original Height = 20)

24/120= 0.2
0.2 x100 = 20
(edited 9 years ago)

Quick Reply

Latest