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    Mm need some help with the following question.
    I don't know what to do next.

    Cheers me dears
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    (Original post by Super199)
    Mm need some help with the following question.
    I don't know what to do next.

    Cheers me dears
    You have got following

    \displaystyle \frac{1-\cos \theta}{\sin \theta}

    Multiply both the numerator and the denominator by 1+\cos \theta

    In the numerator use the identity of (1-\cos \theta)(1+\cos \theta)=1-\cos^2 \theta=\sin^2 \theta

    \sin \theta will be cancelled
    then
    divide both the numerator and denominator by \sin \theta
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    (Original post by ztibor)
    You have got following

    \displaystyle \frac{1-\cos \theta}{\sin \theta}

    Multiply both the numerator and the denominator by 1+\cos \theta

    In the numerator use the identity of (1-\cos \theta)(1+\cos \theta)=1-\cos^2 \theta=\sin^2 \theta

    \sin \theta will be cancelled
    then
    divide both the numerator and denominator by \sin \theta
    Small correction in the last step

    divide both the numerator and denominator by \cos \theta
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    (Original post by Tutorsos)
    Small correction in the last step

    divide both the numerator and denominator by \cos \theta
    OK. Thanks
 
 
 
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