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Odd and Even Functions Problem

The function f is defined of -3<=x<=3 Given that F:x -> x^2-3x 0<=x<=3
sketch y=f(x) in the cases where F is (i) Odd (ii) Even.

Everyone in my further maths class is stuck on this question, if anyone could help would be great :biggrin:

Reply 1

ghostwalker

Original post by gibby97

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Do you have a scan/link to the original question - as it stands that doesn't make much sense.

Reply 2

davros

Original post by ghostwalker

Do you have a scan/link to the original question - as it stands that doesn't make much sense.

Isn't it just a case of plotting x^2 - 3x for 0 <= x <= 3 and then plotting the appropriate reflection for -3 <= x <= 0 to make either an odd or an even function?

Reply 3

ghostwalker

Original post by davros

Isn't it just a case of plotting x^2 - 3x for 0 <= x <= 3 and then plotting the appropriate reflection for -3 <= x <= 0 to make either an odd or an even function?