Why is x^3(7x^2+7x+6) = x(7x^2+7x+6)^3 ? Watch

romama
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Can someone please explain this because when I sub x for any number the results are different when the exponent is in a different place. :3
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0x2a
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That isn't generally true, it's only true when x = 0 (or some other root of the polynomial you create, if it has roots that is).

EDIT: I'm assuming you mean x^3(7x^2 + 7x + 6) = x(7x^2 + 7x + 6)^3.
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TenOfThem
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(Original post by romama)
Can someone please explain this because when I sub x for any number the results are different when the exponent is in a different place. :3
It isn't

why did you think that it was?
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TeeEm
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(Original post by romama)
Can someone please explain this because when I sub x for any number the results are different when the exponent is in a different place. :3
is this an equation to solve?
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Noble.
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The left hand side is a degree 5 polynomial, while the right hand side a 7...
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davros
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(Original post by romama)
Can someone please explain this because when I sub x for any number the results are different when the exponent is in a different place. :3
It isn't true in general if you've written it correctly!!
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tombayes
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(Original post by romama)
Can someone please explain this because when I sub x for any number the results are different when the exponent is in a different place. :3
there are only seven values of x for which this is true. The only real one being 0 (other 6 are complex).
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