# Infinite geometric SequencesWatch

#1
After the chart, there is the explanation about the limits and i cant understand it.

if someone could help me and explain the expplanation about the limit (maybe in simple words) I would be really thankful

Thank you
0
4 years ago
#2
(Original post by sabi06)
After the chart, there is the explanation about the limits and i cant understand it.
????

0
4 years ago
#3
(Original post by sabi06)
After the chart, there is the explanation about the limits and i cant understand it.

if someone could help me and explain the expplanation about the limit (maybe in simple words) I would be really thankful

Thank you
look in the formula above the chart

it says that if you add a lot of terms, in other words n is very very large (1/2)n is practically zero

[raise 1/2 to larger and larger powers]

so the final answer (after tidy is 2)
0
#4
(Original post by TeeEm)
????

I put a picture...it cant be seen?
0
4 years ago
#5
(Original post by sabi06)
I put a picture...it cant be seen?
I do now.

see if it helps
0
#6
(Original post by TeeEm)
look in the formula above the chart

it says that if you add a lot of terms, in other words n is very very large (1/2)n is practically zero

[raise 1/2 to larger and larger powers]

so the final answer (after tidy is 2)
so as n gets larger it gets closer to 2 and therfore the limit is 2 but i didnt understand what zero has to do with it
0
4 years ago
#7
(Original post by sabi06)
so as n gets larger it gets closer to 2 and therfore the limit is 2 but i didnt understand what zero has to do with it
As n gets larges, (1/2)^n gets very close to 0. This is where the zero comes into it.
0
4 years ago
#8
(Original post by sabi06)
so as n gets larger it gets closer to 2 and therfore the limit is 2 but i didnt understand what zero has to do with it
NO!

(1/2)n becomes practically zero

type in a calculator larger and larger values for n

so if n gets huge

2[1 - (1/2)n ]becomes 2 x 1 =2
0
#9
(Original post by TeeEm)
NO!

(1/2)n becomes practically zero

type in a calculator larger and larger values for n

so if n gets huge

2[1 - (1/2)n ]becomes 2 x 1 =2
I understood now. so as n gets bigger it gets closer to 0 and when you plug that into the equation it gets closer to 2....am i right?
why does this happen?
0
4 years ago
#10
(Original post by sabi06)
I understood now. so as n gets bigger it gets closer to 0 and when you plug that into the equation it gets closer to 2....am i right?
why does this happen?
(1/2)n becomes practically zero as you put lager and larger n

so The whole thing eventually (in this case) becomes 2 x 1 =2

why does it happen?

well think

0.5 x 0.5 = 0.25 smaller
0.5 x 0.5 x 0.5 = 0.125 even smaller
0.5 x 0.5 x 0.5 x 0.5 = 0.0625 even smaller

0.5 x 0.5 x 0.5 x .... 0.5 x 0.5 x 0.5 = tiny ...
0
#11
(Original post by TeeEm)
(1/2)n becomes practically zero as you put lager and larger n

so The whole thing eventually (in this case) becomes 2 x 1 =2

why does it happen?

well think

0.5 x 0.5 = 0.25 smaller
0.5 x 0.5 x 0.5 = 0.125 even smaller
0.5 x 0.5 x 0.5 x 0.5 = 0.0625 even smaller

0.5 x 0.5 x 0.5 x .... 0.5 x 0.5 x 0.5 = tiny ...
thank you, i understood
0
4 years ago
#12
(Original post by sabi06)
thank you, i understood
pleasure
0
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