# Specific Distance QuestionWatch

#1
Hi I'm having some trouble with part (e) of this question.
I dont understand why the answer has used 40.7x2 to calculate the air time.
if s=d/t and the vertical distance is 8114 and the vertical velocity is 399 the t= 20.33...
So thats the time to reach the highest point which i assume is halfway. Therefore 20.33... X 2 will give the total air time right?
But this answer has X2 twice getting 81.6 seconds.

Could someone explain?
0
4 years ago
#2
The time taken to reach the maximum height is 40.7s
You get this from v = u - gt where v = 0 and u = 399m/s and g=9.8m/s/s
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