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longsightdon
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#1
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#1
how do i do this question?

x^2+y^2-6y-7=0
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TeeEm
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(Original post by longsightdon)
how do i do this question?

x^2+y^2-6y-7=0
???? do what ???
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longsightdon
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(Original post by TeeEm)
???? do what ???
oooops find the coordinates of the centre of the circle
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TeeEm
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(Original post by longsightdon)
oooops find the coordinates of the centre of the circle
complete the square in x and in y, then you read it off. I am sure your teacher must have shown you this
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longsightdon
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(Original post by TeeEm)
complete the square in x and in y, then you read it off. I am sure your teacher must have shown you this
but there is only a x^2 and no other x in the equation
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TeeEm
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(Original post by longsightdon)
but there is only a x^2 and no other x in the equation
even better ...

then x2 =(x-0)2, and you should know what that means for a circle.
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longsightdon
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(Original post by TeeEm)
even better ...

then x2 =(x-0)2, and you should know what that means for a circle.
what does that mean?
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TeeEm
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(Original post by longsightdon)
what does that mean?
For instance

(x-2)2+(y+7)2=49 represents a circle centre at (2,-7) radius root(49)=7

then you should be able to work your out
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longsightdon
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(Original post by TeeEm)
For instance

(x-2)2+(y+7)2=49 represents a circle centre at (2,-7) radius root(49)=7

then you should be able to work your out
oh i see thanks
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TeeEm
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#10
(Original post by longsightdon)
oh i see thanks
pleasure
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