Cot Watch

zed963
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#1
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#1
If cot theta = 0

then tan theta = 1/0 so we can't work out the solutions.

So then why do we refer to the cot graph ?

We don't refer to the graph for sec or cosec?
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TenOfThem
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(Original post by zed963)
If cot theta = 0

then tan theta = 1/0 so we can't work out the solutions.
If a fraction=0 then the numerator of that fraction=0

SO you can find the solutions



So then why do we refer to the cot graph ?

We don't refer to the graph for sec or cosec?
I have no idea what you are asking here
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zed963
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(Original post by TenOfThem)
If a fraction=0 then the numerator of that fraction=0

SO you can find the solutions





I have no idea what you are asking here
Okay so if 1/0 = 0

then tan =0

and theta can =0,180,360

but the values for cot are different? 90 and 270.
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TenOfThem
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(Original post by zed963)
Okay so if 1/0 = 0

then tan =0

and theta can =0,180,360

but the values for cot are different? 90 and 270.
1/0 does not = 1
That makes no sense


You said cot(x) = 0

Do you know that cot(x) = cos(x)/sin(x)
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zed963
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(Original post by TenOfThem)
1/0 does not = 1
That makes no sense


You said cot(x) = 0

Do you know that cot(x) = cos(x)/sin(x)
Okay so how would you go about finding the solutions for cot(x)=0 ?
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TenOfThem
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(Original post by zed963)
Okay so how would you go about finding the solutions for cot(x)=0 ?
I told you that in my first post

A fraction=0 means that the numerator=0

And Cot(x) can be written as a fraction
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zed963
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(Original post by TenOfThem)
I told you that in my first post

A fraction=0 means that the numerator=0

And Cot(x) can be written as a fraction
cot(x)=0

1/tan(x) =0

therefore tan(x)=0

Correct so far?
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TenOfThem
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(Original post by zed963)
cot(x)=0

1/tan(x) =0

therefore tan(x)=0

Correct so far?
No
You know that this is not correct

\cot(x) = \dfrac{\cos(x)}{\sin(x)}= 0

Do you know what the numerator is?
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zed963
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(Original post by TenOfThem)
No
You know that this is not correct

\cot(x) = \dfrac{\cos(x)}{\sin(x)}= 0

Do you know what the numerator is?
I thought you said it was 0
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TenOfThem
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(Original post by zed963)
I thought you said it was 0
seriously?



do you actually know what i mean by numerator?
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davros
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(Original post by zed963)
I thought you said it was 0
Do you know what the numerator of a fraction is?

If a/b = 0 then a = 0.
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zed963
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(Original post by TenOfThem)
seriously?



do you actually know what i mean by numerator?
(Original post by davros)
Do you know what the numerator of a fraction is?

If a/b = 0 then a = 0.
Yes I understand that but I don't seem to understand what you're trying to imply.
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Super199
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(Original post by zed963)
Yes I understand that but I don't seem to understand what you're trying to imply.
Cot(x) = 0 where cos(x) = 0
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zed963
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(Original post by Super199)
Cot(x) = 0 where cos(x) = 0
Where've you got that from?
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Super199
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(Original post by zed963)
Where've you got that from?
Have you not bothered reading any of the other posts?
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TenOfThem
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(Original post by zed963)
Where've you got that from?
Seriously?

Which part do you not understand?
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zed963
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(Original post by TenOfThem)
Seriously?

Which part do you not understand?
Ooooh, I see

cot = cos / sin

therefore cos=0

Aah, now it all makes sense.

Thanks.
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davros
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(Original post by zed963)
Ooooh, I see

cot = cos / sin

therefore cos=0

Aah, now it all makes sense.

Thanks.
Glad you got there in the end!

There is another way of looking at cot.

Cot is short for cotangent i.e. "complementary tangent" i.e. the tangent of the complementary angle in a right angled triangle. If the 2 angles in a right angled triangle are A and B (apart from the right angle) then tan A = cot B and vice versa i.e. cot A = tan(90 - A).

So if you're trying to solve cot X = 0 that is exactly the same as trying to solve tan(90 - X) = 0. I assume you wouldn't have a problem solving that
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