# Maths C1 Series and SequencesWatch

Thread starter 4 years ago
#1
Hi,
Im stuck on this question: "Prove that the (2n+1)th term of the sequence Un=n^2 -1 is a multiple of 4."

I've substituted the "(2n+1)" as "n" into the formula and got "U 2n+1=4n^2+4n+1-1" so i ended up with "U2n+1=4n^2+4n"... I don't know what to do from here on...

Help would be great, thanks
0
4 years ago
#2
(Original post by Arman47)
Hi,
Im stuck on this question: "Prove that the (2n+1)th term of the sequence Un=n^2 -1 is a multiple of 4."

I've substituted the "(2n+1)" as "n" into the formula and got "U 2n+1=4n^2+4n+1-1" so i ended up with "U2n+1=4n^2+4n"... I don't know what to do from here on...

Help would be great, thanks
Moved to the maths forum for you
0
4 years ago
#3
(Original post by Arman47)
Hi,
Im stuck on this question: "Prove that the (2n+1)th term of the sequence Un=n^2 -1 is a multiple of 4."

I've substituted the "(2n+1)" as "n" into the formula and got "U 2n+1=4n^2+4n+1-1" so i ended up with "U2n+1=4n^2+4n"... I don't know what to do from here on...

Help would be great, thanks
Are you saying that you have and you cannot show that it is a multiple of 4?
0
Thread starter 4 years ago
#4
(Original post by TenOfThem)
Are you saying that you have and you cannot show that it is a multiple of 4?
In the answer section it says "Un=4n^2+4n" so i got confused because i ended up with "U2n+1=4n^2+4n"...
0
Thread starter 4 years ago
#5
(Original post by She-Ra)
Moved to the maths forum for you
Thanks ^___^
0
4 years ago
#6
(Original post by Arman47)
In the answer section it says "Un=4n^2+4n" so i got confused because i ended up with "U2n+1=4n^2+4n"...

Is the answer that you are looking for
0
Thread starter 4 years ago
#7
Thanks
0
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