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# P3 Maths Integration Question watch

1. I'M DOING A PST PASER AT THE MOMENT AND I'M HAVING A BIT OF TROUBLE. MAYBE U GUYS COULD HELP ME. THE QUESTION IS QUESTION 3 FROM AN OCR P3 PAPER DATED 11 JUNE 2002 IF THAT HELPS

ANYWAY THE QUESTION IS "FIND THE SOLUTION OF THE DIFFERENTIAL EQUATION: dy/dx = (X*4 - 1)/(x*2 y*2)

given that y=2 when x=1
by the way x*4 means x to the power 4, x*2 means x squared and y*2 means y squared.

i know that the last part is used to find the constant at the end, but the trouble is i can't even intergrate the equation in the first place. can anyone help me with finding the answer. please show ur working.
2. You should "separate the variables". That is, write the DE as

(something involving y only) * dy/dx = (something involving x only).

Then integrate both sides wrt x, using the fact that

(int) [(something involving y only) * dy/dx] dx
= (int) (something involving y only) dy.
3. (Original post by DLo)
I'M DOING A PST PASER AT THE MOMENT AND I'M HAVING A BIT OF TROUBLE. MAYBE U GUYS COULD HELP ME. THE QUESTION IS QUESTION 3 FROM AN OCR P3 PAPER DATED 11 JUNE 2002 IF THAT HELPS

ANYWAY THE QUESTION IS "FIND THE SOLUTION OF THE DIFFERENTIAL EQUATION: dy/dx = (X*4 - 1)/(x*2 y*2)

given that y=2 when x=1
by the way x*4 means x to the power 4, x*2 means x squared and y*2 means y squared.

i know that the last part is used to find the constant at the end, but the trouble is i can't even intergrate the equation in the first place. can anyone help me with finding the answer. please show ur working.
assuming that X=x (see quote),
multiply both sides by y^2 (y^2 means y-squared)
then integral y^2 dy = integral (x^4-1)/x^2 dx
4. y^3=x^3-3/x+10
5. cheers for all ur help guys
it all makes sense now

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