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Proportionality question
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Peanut247
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davros
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Peanut247
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#3
(Original post by davros)
Do you know how to rewrite a statement like "x is directly proportional to the square of z" in terms of indices and some unknown constant(s)?
Do you know how to rewrite a statement like "x is directly proportional to the square of z" in terms of indices and some unknown constant(s)?
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TenOfThem
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davros
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#5
(Original post by Peanut247)
x [directly proportional to] k(z^2)
x [directly proportional to] k(z^2)
Now you should be able to write something similar for the case of inverse proportion
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Peanut247
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#6
(Original post by davros)
Not quite - see TenOfThem's correction!
Now you should be able to write something similar for the case of inverse proportion
Not quite - see TenOfThem's correction!
Now you should be able to write something similar for the case of inverse proportion
y=1/(z^3)
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TenOfThem
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davros
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#8
(Original post by Peanut247)
y=1/(z^3)
y=1/(z^3)
Now you just need to combine these things in various ways
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Peanut247
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#9
(Original post by davros)
Again, see TenOfThem's correction - you missed out the constant!!
Now you just need to combine these things in various ways
Again, see TenOfThem's correction - you missed out the constant!!
Now you just need to combine these things in various ways
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Peanut247
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TenOfThem
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#11
(Original post by Peanut247)
This was the bit I got stuck on.. I tried making them both equal z but just flopped!
This was the bit I got stuck on.. I tried making them both equal z but just flopped!
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Peanut247
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#12
x=kz^2 becomes x^3 = kz^6
So x^3 = 1/y^2 making the answer D?
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TenOfThem
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#13
(Original post by Peanut247)
y=k/z^3 becomes 1/y^2 = k^2z^6
x=kz^2 becomes x^3 = k^3z^6
So x^3 = k/y^2 making the answer D?
y=k/z^3 becomes 1/y^2 = k^2z^6
x=kz^2 becomes x^3 = k^3z^6
So x^3 = k/y^2 making the answer D?
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