Calculations of product/reactant -- plzz help

hey guys, i really need help on this:

What mass of barium sulphate would be produced from 10g of barium chloride in the following reaction?

BaCl2 + H2SO4 ---------> BaSO4 + 2HCL

Thank u very much for ur time :smile:

Reply 1

vinny221

10/208=0.048 moles of barium chloride

therefore 0.048 moles of barium sulphate so:

0.048x233=11.2g

Reply 2

Revd. Mike

This was the one thing i never could do, yield calculation. Not sure why. My teacher sometimes jokingly tells me off for knowing degree level chemistry, but I still can't manage these. Funny world.

Reply 3

Borek

Very basic stoichiometric calculations.

Reply 4

Revd. Mike

I like the section: "When Balancing Fails" :biggrin:

Reply 5

Doji

lol thnx vinny221 ...and i also find it hard..but i dnt knw degree chem lmao

Reply 6

steve2005

Zakz

I know you have been given the answer, but, I always used to find ratio the easiest way to solve this kind of problem.

Picture 54.png15.6KB

Reply 7

Doji

that was awesomely helpful...but where did u get 10 from? and why did u multiply 233 by the 10?

thanks

Reply 8

steve2005

Zakz

that was awesomely helpful...but where did u get 10 from? and why did u multiply 233 by the 10?

thanks

The question was "How much ....sulphate can you produce from 10g of chloride.

A balanced chemical equation tells you the masses of reactant and the masses of product.

208 g of chloride produce 233 g of sulphate
so 1 g of chloride would prodeuce 233 divided by 208
s0 10 g of chloiride produce 10 times as much. i. e 10 x 233 / 208