# rationalising surds

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#1
How would you go about rationalising something where the denominator is all in brackets like:

(2 + √3)^2
0
7 years ago
#2
(Original post by preludefaun)
How would you go about rationalising something where the denominator is all in brackets like:

(2 + √3)^2

Posted from TSR Mobile
0
7 years ago
#3
(Original post by preludefaun)
How would you go about rationalising something where the denominator is all in brackets like:

(2 + √3)^2
I don't see a denominator there. 0.o

Could you simply FOIL out the 2​?
0
7 years ago
#4
(Original post by anosmianAcrimony)
I don't see a denominator there. 0.o

Could you simply FOIL out the 2​?
he is saying that is the denominator

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#5
The full question is to rationalise:

3√2 - 2√3 / (√2 + √3)^2
0
7 years ago
#6
(Original post by preludefaun)
How would you go about rationalising something where the denominator is all in brackets like:

(2 + √3)^2
expand that out and u will an answer in the form a+broot(3) and then carry on as u normally would by multiplying top and bottom by a-broot(3). find a and b by urself

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#7
Yeah I think I'm just going to expand the denominator out then rationalise.
0
7 years ago
#8
(Original post by physicsmaths)
he is saying that is the denominator

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Oh, I see.
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7 years ago
#9
ignore my previous post as i read it wrong. expand root 2 + root 3 squared and see whatu get. u shud get something in the form a+broot(6). after that rationalise normally

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0
7 years ago
#10
(Original post by preludefaun)
Yeah I think I'm just going to expand the denominator out then rationalise.
That should do it. Good luck.
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