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salem
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#1
Report Thread starter 17 years ago
#1
Hello!

Please show me step by step how to find the values of linear inequalities in order to make a T-table of those values before I plot them into a graph:

Show graphically the solution of inequality 3y+6x< 8


Best regards,

SALEM
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plasmotron
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#2
no. ive got to wait another 30 seconds before i can post again
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Eru Iluvatar
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Are there any boundary conditions?
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Xenon
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Hey plasmotron, you trying to set a record for the number of posts per day. I wonder what the record for the most number of posts in one day is. Anyone know?
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Eru Iluvatar
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Well ive done about 40 in a day i think.
I didn't count them, but it was at least that.
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Xenon
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No wonder you're on 249 posts.
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Eru Iluvatar
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249???
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Xenon
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Oh whoops, must've read it wrong. Undermining your achievment. Ok then 301 posts.
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m:)ckel
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Hello!

Please show me step by step how to find the values of linear inequalities in order to make a T-table of those values before I plot them into a graph:

Show graphically the solution of inequality 3y+6x< 8


Best regards,

SALEM
basically, this is what i would do:

1. first make x=0, so you get 3y<8, therefore y<2.67. then on a graph plot the point (0,2.67) i.e. 2.67 units up on the y-axis.

2. then make y=0, so you get 6x<8, therefore x<1.33. then on the same graph, plot (1.33,0) i.e. 1.33 units across on the x-axis.

3. then join the two points with a dotted line (since it is just less than. if it were less than or equal to, use a solid line).

4. the solution for the inequality is everyting under the line, since it is less than.

sorry, but i don't know what a T-table is.
hope this helps,
Michael.
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salem
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#10
Report Thread starter 17 years ago
#10
Thanks for the explaination.

In the text book Greer, the author made the following table to plot this equation:

3y+6x < 8

It wa done this way:


3y+6x< 8
y= 8/3 -2x

x= - 3 -2 -1 0 1 2 3 ( values of x)
---------------------------------------------------
8/3 8/3 8/3 8/3 8/3 8/3 8/3 8/3
-2x= 6 4 2 0 -2 -4 -6
---------------------------------------------------
8/3-2x =8.6 6.6 4.6 2.6 0.6 -2.6 -4.6 (values of y)

Your method was much easier and lots of thanks.

Adel S
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#11
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#11
Could i get help step by step how to draw on a graph the region defined by the inequalities:

x>0, y>2x + 1, y + x <8

Thanks
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