This discussion is now closed.
Check out other Related discussions
- CIE AS Level MCQ
- biology multiple choice q
- Accidentally used pencil for aqa a level physics paper 1 MCQ
- OCR B A-level Physics Paper 1 Advancing Physics (H557/01) - 24th May 2024 [Exam Chat]
- MAT 2024 Post-exam Thoughts
- y13 forecast: a clouded year ahead
- Edexcel AS Physics Paper 1
- UK exams vs US exams - discussion thread
- AQA Economics A level
- LNAT application consideration
- How do unis look at the LNAT
- OCR Physics GCSE Paper 1 (22nd May 2024)
- OCR A Level Business Paper 1 (H431/01) - 14th May 2024 [Exam Chat]
- A*/A in A-Level Economics (Specifically OCR students)
- Seriously all you need to get an A/A* in A-Level Economics
- A*A-Level Economics Resources - 40+ Pages of unique application/evaluation
- A-level exam boards
- Want to improve your A-Level Economics grade? read this.
- LNAT Advice (Section A)
- Senior Physics Challenge 2022
A level Physics MCQ
Can someone help me in this question please?
A cyclist is capable of generating an average power of 3.0kW during a 4.0 km speed trial.
His aerodynamic suit and position on the cycle reduce resistive forces to 180N.
What is the approximate time achieved in the speed trial?
A 140s
B 240s
C 1300s
D 2200s
thanks
A cyclist is capable of generating an average power of 3.0kW during a 4.0 km speed trial.
His aerodynamic suit and position on the cycle reduce resistive forces to 180N.
What is the approximate time achieved in the speed trial?
A 140s
B 240s
C 1300s
D 2200s
thanks
~jackie~
Can someone help me in this question please?
A cyclist is capable of generating an average power of 3.0kW during a 4.0 km speed trial.
His aerodynamic suit and position on the cycle reduce resistive forces to 180N.
What is the approximate time achieved in the speed trial?
A 140s
B 240s
C 1300s
D 2200s
thanks
A cyclist is capable of generating an average power of 3.0kW during a 4.0 km speed trial.
His aerodynamic suit and position on the cycle reduce resistive forces to 180N.
What is the approximate time achieved in the speed trial?
A 140s
B 240s
C 1300s
D 2200s
thanks
Right, well the important point here is that you assume he travels at a constant speed. This means that there is no resultant force and so he/ she applies a force of 180N.
Now Work = Force * distance, both of which you know
And power it work/ time so you can work out the time by rearranging. I'll leave you to work it out.
P=F*d/t
Related discussions
- CIE AS Level MCQ
- biology multiple choice q
- Accidentally used pencil for aqa a level physics paper 1 MCQ
- OCR B A-level Physics Paper 1 Advancing Physics (H557/01) - 24th May 2024 [Exam Chat]
- MAT 2024 Post-exam Thoughts
- y13 forecast: a clouded year ahead
- Edexcel AS Physics Paper 1
- UK exams vs US exams - discussion thread
- AQA Economics A level
- LNAT application consideration
- How do unis look at the LNAT
- OCR Physics GCSE Paper 1 (22nd May 2024)
- OCR A Level Business Paper 1 (H431/01) - 14th May 2024 [Exam Chat]
- A*/A in A-Level Economics (Specifically OCR students)
- Seriously all you need to get an A/A* in A-Level Economics
- A*A-Level Economics Resources - 40+ Pages of unique application/evaluation
- A-level exam boards
- Want to improve your A-Level Economics grade? read this.
- LNAT Advice (Section A)
- Senior Physics Challenge 2022
Latest
Trending
