# Mathematics C1 - Differentiation

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V.D

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#1

How do you answer the following questions (it says 'use standard results to differentiate

1a) 2√x

b) 3 divided by x²

c) 1 divided by 3x

d)one thirdx

e)2 divided by x

f)

g)2x + 3 divided by x

h)3x² - 6 divided by x

i) 2x

j) x(x² - x + 2)

k) 3x²(x² + 2x)

l) (3x - 2)(4x + 1 over x)

1a) 2√x

b) 3 divided by x²

c) 1 divided by 3x

^{3}d)one thirdx

^{3}(x - 2)e)2 divided by x

^{3}+ √xf)

^{3}√x + 1 divided 2xg)2x + 3 divided by x

h)3x² - 6 divided by x

i) 2x

^{3}+ 3x divided by √xj) x(x² - x + 2)

k) 3x²(x² + 2x)

l) (3x - 2)(4x + 1 over x)

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davros

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#2

(Original post by

How do you answer the following questions (it says 'use standard results to differentiate

1a) 2√x

b) 3 divided by x²

c) 1 divided by 3x

d)one thirdx

e)2 divided by x

f)

g)2x + 3 divided by x

h)3x² - 6 divided by x

i) 2x

j) x(x² - x + 2)

k) 3x²(x² + 2x)

l) (3x - 2)(4x + 1 over x)

**V.D**)How do you answer the following questions (it says 'use standard results to differentiate

1a) 2√x

b) 3 divided by x²

c) 1 divided by 3x

^{3}d)one thirdx

^{3}(x - 2)e)2 divided by x

^{3}+ √xf)

^{3}√x + 1 divided 2xg)2x + 3 divided by x

h)3x² - 6 divided by x

i) 2x

^{3}+ 3x divided by √xj) x(x² - x + 2)

k) 3x²(x² + 2x)

l) (3x - 2)(4x + 1 over x)

What standard methods have you covered in class?

If you've been through the standard rules for differentiation, then all of these should be straighforward!

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Malgorithm

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#3

**V.D**)

How do you answer the following questions (it says 'use standard results to differentiate

1a) 2√x

b) 3 divided by x²

c) 1 divided by 3x

^{3}

d)one thirdx

^{3}(x - 2)

e)2 divided by x

^{3}+ √x

f)

^{3}√x + 1 divided 2x

g)2x + 3 divided by x

h)3x² - 6 divided by x

i) 2x

^{3}+ 3x divided by √x

j) x(x² - x + 2)

k) 3x²(x² + 2x)

l) (3x - 2)(4x + 1 over x)

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Nuvertion

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#4

(Original post by

For the first one, you should know that can be written as . In order to differentiate an equation in C1, you need to get all terms to be x to the power of something. Some of these you should be able to expand or rearrange to get in this form. Then just differentiate using what you should have been taught in class.

**Malgorithm**)For the first one, you should know that can be written as . In order to differentiate an equation in C1, you need to get all terms to be x to the power of something. Some of these you should be able to expand or rearrange to get in this form. Then just differentiate using what you should have been taught in class.

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victoria98

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#5

Where applicable, use the rules of indices to make life easier, and then just do what you'd normally do to differentiate. If you're not sure how to do that you can ask, or read your textbook. We can't do your homework for you!

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V.D

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#6

(Original post by

We're not just going to give you the answers

What standard methods have you covered in class?

If you've been through the standard rules for differentiation, then all of these should be straighforward!

**davros**)We're not just going to give you the answers

What standard methods have you covered in class?

If you've been through the standard rules for differentiation, then all of these should be straighforward!

then dy/dx = anx to the power 1 minus 1

so i know x² = 2x

but i don't know what to do when there is a 3 above the x²

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V.D

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#7

(Original post by

Where applicable, use the rules of indices to make life easier, and then just do what you'd normally do to differentiate. If you're not sure how to do that you can ask, or read your textbook. We can't do your homework for you!

Posted from TSR Mobile

**victoria98**)Where applicable, use the rules of indices to make life easier, and then just do what you'd normally do to differentiate. If you're not sure how to do that you can ask, or read your textbook. We can't do your homework for you!

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Jordan97

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#8

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#8

(Original post by

well i know if y= ax to the power n (where a is a constant)

then dy/dx = anx to the power 1 minus 1

so i know x² = 2x

but i don't know what to do when there is a 3 above the x²

**V.D**)well i know if y= ax to the power n (where a is a constant)

then dy/dx = anx to the power 1 minus 1

so i know x² = 2x

but i don't know what to do when there is a 3 above the x²

Remember that x^-n = 1/x^n

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davros

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#9

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#9

**V.D**)

well i know if y= ax to the power n (where a is a constant)

then dy/dx = anx to the power 1 minus 1

so i know x² = 2x

but i don't know what to do when there is a 3 above the x²

Now you can apply your "standard rule" for differentiation.

Follow a similar process for all the others.

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Malgorithm

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#10

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#11

(Original post by

You need to begin by getting rid of the fraction

Remember that x^-n = 1/x^n

**Jordan97**)You need to begin by getting rid of the fraction

Remember that x^-n = 1/x^n

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victoria98

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#12

(Original post by

It's not homework it's a small section of my revision

**V.D**)It's not homework it's a small section of my revision

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#13

(Original post by

This is just GCSE stuff!

Now you can apply your "standard rule" for differentiation.

Follow a similar process for all the others.

**davros**)This is just GCSE stuff!

Now you can apply your "standard rule" for differentiation.

Follow a similar process for all the others.

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victoria98

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#14

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#14

Once you get x^something. Multiply the coefficient of x by the power of x, then drop the power by one. E.g. X^2 + 2x + 6 becomes 2x + 2

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Jordan97

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#15

(Original post by

i never learnt that above rule before, can you write it in words (i don't understand ^ means)

**V.D**)i never learnt that above rule before, can you write it in words (i don't understand ^ means)

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davros

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#16

(Original post by

can you show me the steps of how you came to your answer

**V.D**)can you show me the steps of how you came to your answer

You know that from GCSE. Therefore

Now apply your standard rule to differentiate this giving

Follow a similar process to attack all the others

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#17

Gaiaphage

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#18

(Original post by

can you show me the steps of how you came to your answer

**V.D**)can you show me the steps of how you came to your answer

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#19

(Original post by

You said this was revision - "revision" means "seeing again" i.e. there should be nothing unfamiliar in all this for you!

You know that from GCSE. Therefore

Now apply your standard rule to differentiate this giving

Follow a similar process to attack all the others

**davros**)You said this was revision - "revision" means "seeing again" i.e. there should be nothing unfamiliar in all this for you!

You know that from GCSE. Therefore

Now apply your standard rule to differentiate this giving

Follow a similar process to attack all the others

^{3}will equal -9x^-

^{3}

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#20

You've gone wrong in 2 places if that's the case.

It might be a good idea to talk to your Maths teacher in the morning about this exercise as you don't seem to have covered some of the basic rules properly in class

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