how do i find the length between the centre and one of the 'corners'?
You don't need to find that length as it wouldn't help you work out the are directly.
What you do need to find it the height of each triangel (the perendiclr ditance from the centre of one side to the entre of the pentagon (see the blue line in the diagram). That can be done using trigonometry.
Add an extra line inside the pentagon dividing it into a triangle and a trapezium. Since it is a regular pentagon its internal angles are 108 degrees. Using this with the cosine rule you can calculate the length of the extra line. You can then find the area of the trapezium and triangle, add them together to get the area of the pentagon.
Divide the pentagon into 5 isoceles triangles. For each triangle, the angle at the centre of the pentagon is 2pi/5. The pentagon has 5 vertices, or corners. The sum of the angles at the vertices of an n-sided polygon is equal to pi(n-2). You now have a triangle where you know all the angles of it and also you have the length of one of the sides. You can work out the area of such a triangle.