# Linear map between polynomialsWatch

#1
Hi tsr,

I don't know how to go about finding the matrix describing this linear transformation, all I know is that the basis for this would be (1,x,x^2) and apart from that I don't understand what to do next.

Any help would be much appreciated.
0
4 years ago
#2
Well, what does 1 map to under f->f' ? (i.e. literally, what do you get if you differentiate 1)?
What does x map to?
What does x^2 map to?

So the matrix is...?
0
#3
(Original post by DFranklin)
Well, what does 1 map to under f->f' ? (i.e. literally, what do you get if you differentiate 1)?
What does x map to?
What does x^2 map to?

So the matrix is...?
Yes got it now thanks. First column would be (0,0,0) followed by (1,0,0) and (0,2,0).
0
4 years ago
#4
There is no need to find the matrix for this question. An eigenvalue is just a constant c such that L(f)=cf for some f. You can calculate this directly without using the matrix.
0
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