C4 maths helpWatch

#1
0

4 years ago
#2
Well what have you done so far? If you really don't know where to start, think about the cos and sine graphs and how they look like.
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#3
(Original post by Chlorophile)
Well what have you done so far? If you really don't know where to start, think about the cos and sine graphs and how they look like.
ai) I got 1 and -1
aii) 2 and -2

b) Rearranging for t but I do not know how to

c) Make x and y 0 but I can't rearrange from part b)
0
4 years ago
#4
(Original post by frozo123)
ai) I got 1 and -1
aii) 2 and -2

b) Rearranging for t but I do not know how to

c) Make x and y 0 but I can't rearrange from part b)

For b, remember that sin^2(t)+cos^2(t)=1. Try to rearrange y=sin^2(2t) into the form sin(t)=...
0
#5
(Original post by Chlorophile)

For b, remember that sin^2(t)+cos^2(t)=1. Try to rearrange y=sin^2(2t) into the form sin(t)=...
will it be 0.5 then 0.5 squared is 0.25 so -0.25 and 0.25?
0
4 years ago
#6
(Original post by frozo123)
will it be 0.5 then 0.5 squared is 0.25 so -0.25 and 0.25?
For a.ii? No! The maximum value of sin(2t) is the same as the maximum value of sin(t). The 2t only squashes it horizontally, it still has the exact same maximum and minimum values as the ordinary sine curve. If we were talking about 0.5sin(t) then you'd be correct, but we're not.
0
#7
(Original post by Chlorophile)
For a.ii? No! The maximum value of sin(2t) is the same as the maximum value of sin(t). The 2t only squashes it horizontally, it still has the exact same maximum and minimum values as the ordinary sine curve. If we were talking about 0.5sin(t) then you'd be correct, but we're not.
Okay that makes sense for a) thankyou
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