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    1) the velocity of a particle is given by v= (16t^2)i + (4t^3)j + (5t + 2)k m/s, where t is in seconds. If the particle is at the origin when t=0, determine the magnitude of the particle's acceleration when t=2s. Also, what is the x,y,z cooridnate position of the particle at this instant?

    2) Balll A is released from rest at a height of 40ft at the same time that a second ball B is thrown 5ft from the ground. if the balls pass one another at a height of 20ft, determine the speed at which the ball b was thrown upward.

    3) when a rocket reaches an altitude of 40m it begins to travel along the parabolic path (y-40)^2 = 160x, where the coordinates are measured in meters. If the component of velocity in the vertical direction is constant at Vy= 180 m/s, determine the magnitudes of the rockets velocity and acceleration when it reaches an altitude of 80m.

    plz help me!!
    thanks
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    1) I get 37.1 ms^-2

    and at that point 64i + 32j + 12K.
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    how did u solve it?!
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    Is it right?
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    yes
 
 
 
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Updated: October 9, 2006

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