Titration results table Watch

BrokenS0ulz
Badges: 3
Rep:
?
#1
Report Thread starter 4 years ago
#1
I have a titre which requires multiple runs of the burette for the end point to be reached. Does anybody know what the conventional way to record this data is? I've done it like this but I don't know if it's easy to understand.

Attached files
0
reply
harper_
Badges: 1
Rep:
?
#2
Report 4 years ago
#2
------------------------------Rough-----Run 1-----Run 2-----Run 3

Initial Reading (cm^3)
Final Reading (cm^3)
Titre (cm^3)

Hyphens instead of spaces...
0
reply
langlitz
Badges: 17
Rep:
?
#3
Report 4 years ago
#3
(Original post by BrokenS0ulz)
I have a titre which requires multiple runs of the burette for the end point to be reached. Does anybody know what the conventional way to record this data is? I've done it like this but I don't know if it's easy to understand.

Those titres aren't concordant, also you'd want the average volume not the total.
0
reply
BrokenS0ulz
Badges: 3
Rep:
?
#4
Report Thread starter 4 years ago
#4
(Original post by harper_)
------------------------------Rough-----Run 1-----Run 2-----Run 3

Initial Reading (cm^3)
Final Reading (cm^3)
Titre (cm^3)

Hyphens instead of spaces...
Thank you

(Original post by langlitz)
Those titres aren't concordant, also you'd want the average volume not the total.
They aren't averages, I had to run the burette 3 times for the end point to work. So the titre was 137.75cm^3 I don't know how to write that properly in a table though.
0
reply
Pigster
Badges: 17
Rep:
?
#5
Report 4 years ago
#5
You should decrease the conc. of the chemical in the burette by a factor of five OR reduce the amount of chemical in the conical by a factor of five. That way you'll use about 25 cm3 of titrant. Using the burette multiple times like that is not best practice; you're introducing equipment uncertainties.
0
reply
langlitz
Badges: 17
Rep:
?
#6
Report 4 years ago
#6
(Original post by BrokenS0ulz)
Thank you



They aren't averages, I had to run the burette 3 times for the end point to work. So the titre was 137.75cm^3 I don't know how to write that properly in a table though.
Oh right.. As pigster said, you should decrease the concentration. Ideally you don't want to have to refill the burette half way through a titre, although sometimes it is unavoidable.
0
reply
BrokenS0ulz
Badges: 3
Rep:
?
#7
Report Thread starter 4 years ago
#7
(Original post by langlitz)
Oh right.. As pigster said, you should decrease the concentration. Ideally you don't want to have to refill the burette half way through a titre, although sometimes it is unavoidable.

(Original post by Pigster)
You should decrease the conc. of the chemical in the burette by a factor of five OR reduce the amount of chemical in the conical by a factor of five. That way you'll use about 25 cm3 of titrant. Using the burette multiple times like that is not best practice; you're introducing equipment uncertainties.
Thanks for the replies. I didn't know how much it would take so after the rough titration I did a 1 in 10 dilution and decreased the amount in the conical flask and got suitable titres. I need to include the rough titration though. Is there a clearer way to record the data?
0
reply
mollyxrose
Badges: 12
Rep:
?
#8
Report 4 years ago
#8
http://www.ocr.org.uk/Images/70646-p...s-handbook.pdf

I've been told to record my results in a table as seen on page 30 of this handbook. I think it's pretty easy to understand, but if you want a written table that includes results for reference, I'd be happy to send you a picture.
1
reply
chuckster111
Badges: 3
Rep:
?
#9
Report 4 years ago
#9
How do you find the concentration of the undiluted solution of the acid in titrations? If possible, could you explain it in terms of ratios e.g. 11.2cm3 (result of titre) : 0.002654 mol (moles in that amount).

My ISA's tomorrow
0
reply
langlitz
Badges: 17
Rep:
?
#10
Report 4 years ago
#10
(Original post by chuckster111)
How do you find the concentration of the undiluted solution of the acid in titrations? If possible, could you explain it in terms of ratios e.g. 11.2cm3 (result of titre) : 0.002654 mol (moles in that amount).

My ISA's tomorrow
I'm not quite sure what you mean. So 11.2 cm3 of what was required to neutralise an acid? You need to know the concentration of what's in your burette and the balanced equation by which they react. Then you work backwards to work out the concentration/number of moles in your original solution
0
reply
X

Quick Reply

Attached files
Write a reply...
Reply
new posts
Latest
My Feed

See more of what you like on
The Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

Personalise

University open days

  • Cardiff Metropolitan University
    Undergraduate Open Day - Llandaff Campus Undergraduate
    Sat, 27 Apr '19
  • University of East Anglia
    Could you inspire the next generation? Find out more about becoming a Primary teacher with UEA… Postgraduate
    Sat, 27 Apr '19
  • Anglia Ruskin University
    Health, Education, Medicine and Social Care; Arts, Humanities and Social Sciences; Business and Law; Science and Engineering Undergraduate
    Sat, 27 Apr '19

Have you registered to vote?

Yes! (542)
37.74%
No - but I will (112)
7.8%
No - I don't want to (98)
6.82%
No - I can't vote (<18, not in UK, etc) (684)
47.63%

Watched Threads

View All