# Concentration of solutionWatch

#1
Hello, just want to ask what's the difference betwen g/dm^3 and mol/dm^3. Thanks
0
4 years ago
#2
Well if I have idk, not a great example but:

36.5 grams of solid HCl dissolved in 1dm^3
That's 36.5g/dm^3

But Moles = mass/mr so I have 1 mol of it. Which would make it 1moldm^-3 or 1M
0
#3
(Original post by L'Evil Fish)
Well if I have idk, not a great example but:

36.5 grams of solid HCl dissolved in 1dm^3
That's 36.5g/dm^3

But Moles = mass/mr so I have 1 mol of it. Which would make it 1moldm^-3 or 1M
Soooo, it's basically the same right?
0
4 years ago
#4
(Original post by lalala45612)
Soooo, it's basically the same right?
Just different forms
0
4 years ago
#5
No, one is the actual mass per litre of solution and the other is the number of moles per litre.

If you have two different salts with the same mass per litre they will have different moles per litre.
0
4 years ago
#6
(Original post by charco)
No, one is the actual mass per litre of solution and the other is the number of moles per litre.

If you have two different salts with the same mass per litre they will have different moles per litre.
Isn't that obvious?
1
#7
Ok thanks guys =)
0
4 years ago
#8
(Original post by L'Evil Fish)
Isn't that obvious?
Clearly not to the OP
0
4 years ago
#9
How do you find the concentration of the undiluted solution of the acid in titrations? If possible, could you explain it in terms of ratios e.g. 11.2cm3 (result of titre) : 0.002654 mol (moles in that amount).

My ISA's tomorrow
0
4 years ago
#10
(Original post by lalala45612)
Hello, just want to ask what's the difference betwen g/dm^3 and mol/dm^3. Thanks
They are both concentrations of solutions, but written another way, and due to n=m/mr you would convert mol/dm^3 to g/dm^3 by multiplying by the mr of the solution
0
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