# Physics question help...Watch

#1
Points A and B are 0.10m apart. A point charge of +3.0x10(-9) C is placed at A and a point charge of -1.0x10(-9)C is placed at B

X is the point on the straight line through A and B, between A and B where the electric potential is zero. Calculate the distance AX.

The answer was 0.075 however, I am not sure how to mathematically solve this as i kept getting 0.15. Can someone please show me step by step..

Thanks.
0

3 years ago
#2
(Original post by MSB47)
Points A and B are 0.10m apart. A point charge of +3.0x10(-9) C is placed at A and a point charge of -1.0x10(-9)C is placed at B

X is the point on the straight line through A and B, between A and B where the electric potential is zero. Calculate the distance AX.

The answer was 0.075 however, I am not sure how to mathematically solve this as i kept getting 0.15. Can someone please show me step by step..

Thanks.
A has three quarters of the charge difference;

(3 x 10-9)/((3--1) x 10-9)

=3/(3--1)

=Â¾

Hence, the distance AX is Â¾ x 0.1 = 0.075m.
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#3
thanks, this was ages ago when I posted this lool
0
3 years ago
#4
0
3 years ago
#5
(Original post by MSB47)
thanks, this was ages ago when I posted this lool
Didn't notice how long ago that was! At least you can move on with your life now.
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