# Mechanics HelpWatch

#1

Hi, I can't do 11c, can anyone help? Thanks a lot!
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4 years ago
#2
(Original post by kcorbins)

Hi, I can't do 11c, can anyone help? Thanks a lot!
You need to find the time when the particle is rising at velocity k and moving forwards at velocity 4k.
0
4 years ago
#3
(Original post by kcorbins)

Hi, I can't do 11c, can anyone help? Thanks a lot!
The horizontal velocity shall stay constant.

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0
#4
(Original post by Smaug123)
You need to find the time when the particle is rising at velocity k and moving forwards at velocity 4k.
Oh ok, so you'd do simultaneous equations with suvat? And thank you very much for helping me, I really appreciate it!
0
4 years ago
#5
(Original post by kcorbins)
Oh ok, so you'd do simultaneous equations with suvat? And thank you very much for helping me, I really appreciate it!
Yep. I haven't solved the question myself, but that's how it is done.
1
#6
(Original post by physicsmaths)
The horizontal velocity shall stay constant.

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So you need to find the time that the vertical velocity is 1/4 of that? Thanks a lot!
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4 years ago
#7
(Original post by kcorbins)
So you need to find the time that the vertical velocity is 1/4 of that? Thanks a lot!
ill do it trw. post ur working and ill let u know if
you have done kt wrong or right.

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0
4 years ago
#8
(Original post by kcorbins)

Hi, I can't do 11c, can anyone help? Thanks a lot!
find expression V, for the vertical speed in terms of t
horizontal speed U is constant

then V/U = 1/4 ...
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