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# Math equation help AS watch

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1. Find, as surds, the roots of the equation:

2(x+1)(x-4) -(x-2)^2 = 0

I'm not sure of the method.
2. Have you tried expanding the brackets to result in a nicer equation?
3. (Original post by Slowbro93)
Have you tried expanding the brackets to result in a nicer equation?
Yes.
4. (Original post by oneabdi)
Yes.
So what is the quadratic you now have?
5. (Original post by oneabdi)
Yes.

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6. Expand the brackets and simplify. Complete the square or use the quadratic formula to find the roots.

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7. (Original post by oneabdi)
Find, as surds, the roots of the equation:

2(x+1)(x-4) -(x-2)^2 = 0

I'm not sure of the method.
Right, I tied doing it like this but I’m not sure whether itis correct:
2(x+1)(x-4)-(x-2)(x-2)=0
2(x^2-3x-4)-(x^2-4x+4)=0
2x^2-6x-8-x^2+4x-4=0
X^2-2x-12=0
Complete the square:
(x-1)^2-(1)^2=12
(x-1)^2=13
X-1=square root 13
X=1+square root 13 or x= 1-square root 13
8. (Original post by lewisthornton)
2(x+1)(x-4) -(x-2)^2 = 0

(Original post by 08rgill)
...
Please don't post full solutions - it's against forum rules

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