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    Why does the reaction involve water and why isn't H2SO4 directly involved?
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    (Original post by ps1265A)
    Why does the reaction involve water and why isn't H2SO4 directly involved?
    Which reaction?
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    (Original post by charco)
    Which reaction?
    The hydrolysis..? In the title


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    (Original post by William Turtle)
    The hydrolysis..? In the title


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    The title does not mention hydrolysis.

    For hydrolysis you do not use concentrated acid.

    Dilute acid and heat hydrolyses the ester to the alcohol and carboxylic acid ... The hydrogen ions catalyse the reaction.
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    Can you write the equation for the formation of the ester from the acid and the alcohol.

    Can you reverse the (equilibrium) reaction?

    Why would you add H2SO4 for the forward reaction?

    Catalysts lower the activation energy (sorry) in both directions.
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    Hi all, found this forum as i need help with my A level chemistry homework, My teacher has set a range of questions for us to answer, in less we went over hydrolysis with esters which i am find with and now i have homework on this apparently but I am confused from what i just read, my homework is entitled 'carboxylic acid and esters' now i am stuck on these questions:

    1. write equations for the following reactions:
    a. sodium methanoate with hydrochloric acid
    b. sodium ethanoate with sulphuric acid
    c. 2-methylpropanoic acid with sodium carbonate
    2.
    a. ethyl methanoate with concentrated h2so4
    b. methyl propanoate with NaOH
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    (Original post by EpIC_RaGE)
    Bruh just type it into Google, how dumb are you ffs
    I have typed it into google and nothing comes up! only this thats why i put it on this forum ?! i read what the forum had said and now i am confused cause you cant use concentrated H2SO4 apparently
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    I think I have the same HW and am stuck on question 2a on your list;
    The other ones I think I've done correctly, I will write below:

    1.a. Sodium methanoate + HCl --> Methanoic acid + Sodium chloride
    HCOONa + HCl --> HCOOH + NaCl

    1.b. Sodium ethanoate + H2SO4 --> Ethanoic acid + Sodium sulphate
    2CH3COONa + H2SO4 --> 2CH3COOH + Na2SO4

    1.c. 2-methylpropanoic acid + Sodium carbonate --> Sodium 2-methylpropanoate + Water + Carbon dioxide
    2CH3CH(CH3)COOH + Na2CO3 --> 2CH3CH(CH3)COONa + H2O + CO2

    2.b. Methyl propanoate + NaOH --> Sodium propanoate + Methanol
    CH3CH2COOCH3 + NaOH --> CH3CH2COONa + CH3OH
 
 
 
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