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# somebody check my pH calculation watch

1. 50 cm3 of 0.150M HCl added with 500cm3 of water, find pH

so i did

0.150*50/10^3= 7.5x10^-3

i divided 7.5x10^-3 by 550/10^3= 0.01M

i did -log 0.01= 1.87

can someone just clairfy if that is right please
2. As far as i know, its right
3. Ok
4. (Original post by papz_007)
50 cm3 of 0.150M HCl added with 500cm3 of water, find pH

so i did

0.150*50/10^3= 7.5x10^-3

i divided 7.5x10^-3 by 550/10^3= 0.01M

i did -log 0.01= 1.87

can someone just clairfy if that is right please
It is alright. I have checked.

S.Podder

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