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# Another probabl watch

1. The baggage limit for an airplane is set at 100lbs per passanger. Thus, for an airplane with 200 passenger seats there is a limit of 20,000lbs. The weight of the baggage of an individual passenger is a random variable with a mean of 95lbs and a standard deviation of 35lbs. If all 200 seats are sold for a particular flight, what is the probability that the total weight of the passengers' baggage will exceed the 20,000lbs limit?

I'm not sure how to get it. I know y=20,000 and standard deviation is 35 but how do I normalize this so I can find a value in a z table?
2. it's a trick question. nobody will pay for the extra baggage, so the bags heavier than 100lb won't go on the plane. hence the probability of there being more than 20,000lb of baggae on the plane is 0. goodnight.
3. (Original post by chewwy)
it's a trick question. nobody will pay for the extra baggage, so the bags heavier than 100lb won't go on the plane. hence the probability of there being more than 20,000lb of baggae on the plane is 0. goodnight.
Your sarcastic response does point out a major flaw in the question. If the baggage limit is 100lb per passenger, bags over 100lb won't go on the plane. This is, of course, pedantry, and I have nothing useful to say.
4. In no way does the OP imply that all the passengers' baggage would make it on the plane. Therefore, the limit could be broken without the plane being too heavy.
5. Sorry but the answer is .0217. How do you get this?

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