Stuck on summation question (FP2)

Express (2r+3/[r(r+1)] in partial fractions.
Hence, find the sum from r=1 to r=n of (2r+3/[r(r+1)] * 1/(3)^r

I've gotten to the partial fractions as 3/r -1/(r+1)
But I'm not sure how to do the summation by method of differences since there's a 1/3^r term in there...