Maths MEI C3 question Watch

ThatWasHard!
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Hi,

Could someone please help me on part 4 of this question? (Q9)

I'm not really sure where to start..?Name:  ImageUploadedByStudent Room1418572838.843186.jpg
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Cheers for any help, it really is appreciated :')


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ThatWasHard!
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P.s. I am finding the process of inverting the function quite difficult.

Is there an easy trick which I have forgotten?


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TenOfThem
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(Original post by ThatWasHard!)
P.s. I am finding the process of inverting the function quite difficult.

Is there an easy trick which I have forgotten?
You do not need to invert the function

Think about \dfrac{dy}{dx} and \dfrac{dx}{dy}
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ThatWasHard!
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(Original post by TenOfThem)
You do not need to invert the function

Think about \dfrac{dy}{dx} and \dfrac{dx}{dy}
They're reciprocals of each other. But I need the inverse function don't I?




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ThatWasHard!
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(Original post by TenOfThem)
You do not need to invert the function

Think about \dfrac{dy}{dx} and \dfrac{dx}{dy}
Am I supposed to find the reciprocal then integrate?


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Chazatthekeys
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(Original post by ThatWasHard!)
Am I supposed to find the reciprocal then integrate?


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I know now, I just said something stupid before lol!

If we had y=f(x) then the gradient function would be dy/dx

To find the inverse of this function, we would make x the subject, so we'd have x=f(y) [but usually we just change the variable and have y=f^-1(x)]

The gradient of the inverse function is therefore dx/dy

First order differentials behave like fractions so we can say:
dy/dx * dx/dy = 1

So dx/dy = 1 / (dy/dx)
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Chazatthekeys
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(Original post by ThatWasHard!)
Am I supposed to find the reciprocal then integrate?


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It would be pretty hard to find the inverse function of that! Lol don't integrate or do the reciprocal of the function! Lol
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ThatWasHard!
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(Original post by Chazatthekeys)
It would be pretty hard to find the inverse function of that! Lol don't integrate or do the reciprocal of the function! Lol
Aah I get it! Cheers so much! :')


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Chazatthekeys
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(Original post by ThatWasHard!)
Aah I get it! Cheers so much! :')


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No worries! aha, what paper is this?! I couldn't find it lol
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TenOfThem
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(Original post by ThatWasHard!)
Aah I get it! Cheers so much! :')


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Sorry - I went out - Luckily Chaz was on hand
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ThatWasHard!
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(Original post by Chazatthekeys)
No worries! aha, what paper is this?! I couldn't find it lol
It was from the C3 textbook


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Chazatthekeys
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(Original post by ThatWasHard!)
It was from the C3 textbook


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Ah right okay, I went through all the papers to find it lol
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