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    3^(2x+1) = 3^x + 24

    Any help would be much appreciated!
    Thanks!
    xxx
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    ok...

    3^(2x + 1) is the same as 3^x * 3^x * 3^1

    So 3^x * 3^x * 3 = 3^x + 24

    Now let y = 3^x to simplify it a bit

    Then we have:

    3y^2 = y + 24

    From there form a quadratic = 0 and solve to get

    y = 3 or y = -8/3

    But y = 3^x, so either 3^x = 3 ---> x = 1

    or 3^x = -8/3 ---> No real solution

    So x = 1, and if you check:

    3^3 = 3 + 24

    27 = 3 + 24

    Thank you so much!
    I was getting confused over the + 1 part of the first power, but I understand now!
    Cheers mate!
    xxx
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    no problem
 
 
 
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